Exam 11: Simple Linear Regression

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(2, -6)and (-1, 3) (2, -6)and (-1, 3)

(Multiple Choice)
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The dean of the Business School at a small Florida college wishes to determine whether the grade-point average (GPA)of a graduating student can be used to predict the graduateʹs starting Salary. More specifically, the dean wants to know whether higher GPAs lead to higher starting Salaries. Records for 23 of last yearʹs Business School graduates are selected at random, and data On GPA (x)and starting salary (y, in $thousands)for each graduate were used to fit the model E(y)=β0+β1xE ( y ) = \beta _ { 0 } + \beta _ { 1 } ^ { x } The results of the simple linear regression are provided below. =4.25+2.75x, S=5.15,S=1.87 S=15.17,SSE=1.0075 Compute an estimate of σ\sigma , the standard deviation of the random error term.

(Multiple Choice)
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For the situation above, give a practical interpretation of β^0=92040\hat { \beta } _ { 0 } = - 92040 .

(Multiple Choice)
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Plot the line y = 1.5 + .5x. Then give the slope and y-intercept of the line.

(Essay)
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An academic advisor wants to predict the typical starting salary of a graduate at a top business school using the GMAT score of the school as a predictor variable. A simple linear regression of SALARY versus GMAT using 25 data points is shown below. β^0=92040β^1=228s=3213r2=.66r=.81df=23t=6.67\hat { \beta } _ { 0 } = - 92040 \hat { \beta } 1 = 228 s = 3213 r ^ { 2 } = .66 r = .81 \mathrm { df } = 23 \quad t = 6.67 Give a practical interpretation of r=.81r = .81 .

(Multiple Choice)
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A study of the top 75 MBA programs attempted to predict the average starting salary (in $1000's) of graduates of the program based on the amount of tuition (in $1000's)charged by the program. The results of a simple linear regression analysis are shown below: Least Squares Linear Regression of Salary Predictor Variables Coefficient Std Error T P Constant 18.1849 10.3336 1.76 0.0826 Size 1.47494 0.14017 10.52 0.0000 R-Squared 0.6027 \quad 0.6027 \quad Resid. Mean Square (MSE) 532.986 532.986 Adjusted R-Squared 0.5972 0.5972 Standard Deviation 23.0865 \quad 23.0865 The model was then used to create 95%95 \% confidence and prediction intervals for yy and for E(Y)\mathrm { E } ( \mathrm { Y } ) when the tuition charged by the MBA program was $75,000\$ 75,000 . The results are shown here: 95\% confidence interval for E(Y)\mathrm { E } ( \mathrm { Y } ) : ($123,390,$134,220)( \$ 123,390 , \$ 134,220 ) 95%95 \% prediction interval for YY : ($82,476,$175,130)( \$ 82,476 , \$ 175,130 ) Which of the following interpretations is correct if you want to use the model to estimate E(Y)E ( Y ) for all MBA programs?

(Multiple Choice)
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Consider the following pairs of observations: x 2 0 3 3 5 y 1 3 4 6 7 a. Construct a scattergram for the data. b. Find the least squares line, and plot it on your scattergram. c. Find a 99%99 \% confidence interval for the mean value of yy when x=1x = 1 . d. Find a 99%99 \% prediction interval for a new value of yy when x=1x = 1 .

(Essay)
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An academic advisor wants to predict the typical starting salary of a graduate at a top business school using the GMAT score of the school as a predictor variable. A simple linear regression of SALARY versus GMAT was created from a set of 25 data points. Which of the following is not an assumption required for the simple linear regression analysis to Be valid?

(Multiple Choice)
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A high value of the correlation coefficient r implies that a causal relationship exists between x and y.

(True/False)
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Probabilistic models are commonly used to estimate both the mean value of y and a new individual value of y for a particular value of x.

(True/False)
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 Calculate SSE and s2 for n=25,y2=950,y=65,SSxy=3000, and β^1=.2\text { Calculate SSE and } s ^ { 2 } \text { for } n = 25 , \sum y ^ { 2 } = 950 , \sum y = 65 , \mathrm { SS } _ { \mathrm { xy } } = 3000 \text {, and } \hat { \beta } 1 = .2

(Essay)
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A manufacturer of boiler drums wants to use regression to predict the number of man-hours needed to erect drums in the future. The manufacturer collected a random sample of 35 boilers And measured the following two variables: MANHRS: y=\quad y = Number of man-hours required to erect the drum PRESSURE: x=\quad x = Boiler design pressure (pounds per square inch, i.e., psi) The simple linear model E(y)=β1+β1xE ( y ) = \beta 1 + \beta 1 x was fit to the data. A printout for the analysis appears below: UNWEIGHTED LEAST SQUARES LINEAR REGRESSION OF MANHRS PREDICTOR VARIABLES COEFFICIENT STD ERROR STUDENTST P CONSTANT 1.88059 0.58380 3.22 0.0028 PRESSURE 0.00321 0.00163 2.17 0.0300 SOURCE DF SS MS REGRESSION 1 111.008 111.008 5.19 0.0300 RESIDUAL 34 144.656 4.25160 TOTAL 35 255.665 Give a practical interpretation of the coefficient of determination, r2r ^ { 2 } .

(Multiple Choice)
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(-9, 0)and (-4, -1) (-9, 0)and (-4, -1)

(Multiple Choice)
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Is the number of games won by a major league baseball team in a season related to the teamʹs batting average? Data from 14 teams were collected and the summary statistics yield: y=1,134,x=3.642,y2=93,110,x2=.948622, and xy=295.54\sum y = 1,134 , \sum x = 3.642 , \sum y ^ { 2 } = 93,110 , \sum x ^ { 2 } = .948622 , \text { and } \sum x y = 295.54 Assume β^1=455.27\hat { \beta } 1 = 455.27 . Estimate and interpret the estimate of σ\sigma .

(Essay)
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An academic advisor wants to predict the typical starting salary of a graduate at a top business school using the GMAT score of the school as a predictor variable. A simple linear regression of SALARY versus GMAT using 25 data points is shown below. β^0=92040β^1=228s=3213r2=.66r=.81df=23t=6.67\hat { \beta } _ { 0 } = - 92040 \hat { \beta } 1 = 228 s = 3213 r ^ { 2 } = .66 r = .81 \quad \mathrm { df } = 23 \quad t = 6.67 A 95%95 \% prediction interval for SALARY when GMAT =600= 600 is approximately ($37,915,$51,984)( \$ 37,915 , \$ 51,984 ) . Interpret this interval.

(Multiple Choice)
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To investigate the relationship between yield of potatoes, y, and level of fertilizer application, x, a researcher divides a field into eight plots of equal size and applies differing amounts of fertilizer to each. The yield of potatoes (in pounds)and the fertilizer application (in pounds)are recorded for each plot. The data are as follows: x 1 1.5 2 2.5 3 3.5 4 4.5 y 25 31 27 28 36 35 32 34 Summary statistics yield SSxx=10.5,SSyy=112,SSxy=25S S _ { x x } = 10.5 , S S _ { y y } = 112 , S S _ { x y } = 25 , and SSE=52.476S S E = 52.476 . Calculate the coefficient of correlation.

(Essay)
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The least squares model provides very good estimates of y for values of x far outside the range of x values contained in the sample.

(True/False)
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For the situation above, which of the following is not an assumption required for the simple linear regression analysis to be valid?

(Multiple Choice)
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A county real estate appraiser wants to develop a statistical model to predict the appraised value of houses in a section of the county called East Meadow. One of the many variables thought to be An important predictor of appraised value is the number of rooms in the house. Consequently, the Appraiser decided to fit the simple linear regression model: E(y)=β0+β1xE ( y ) = \beta _ { 0 } + \beta 1 ^ { x } where y=y = appraised value of the house (in thousands of dollars) and x=x = number of rooms. Using data collected for a sample of n=84n = 84 houses in East Meadow, the following results were obtained: y^=84.80+19.72x\hat { y } = 84.80 + 19.72 x What are the properties of the least squares line, y=84.80+19.72x?y = 84.80 + 19.72 x ?

(Multiple Choice)
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 Construct a 90% confidence interval for β1 when β^1=49,s=4,SSXX=55, and n=15\text { Construct a } 90 \% \text { confidence interval for } \beta 1 \text { when } \hat { \beta } 1 = 49 , s = 4 , \mathrm { SS } _ { \mathrm { XX } } = 55 \text {, and } n = 15 \text {. }

(Essay)
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