Exam 4: A: Number Theory and Cryptography

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Find the integer a such that a=71(mod47) and 46a0a = 71 ( \bmod 47 ) \text { and } - 46 \leq a \leq 0

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Convert (BC1)16 to base 2 .

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determine whether each of the following "theorems" is true or false. Assume that a, b, c, d, and m are integers with m > 1. -  If ab(mod2m), then ab(modm)\text { If } a \equiv b ( \bmod 2 m ) , \text { then } a \equiv b ( \bmod m )

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What sequence of pseudorandom numbers is generated using the pure multiplicative generator xn+1\mathfrak { x } _ { n + 1 } = 3x mod 11 with seed x0\operatorname {x_0 } =2 ?

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Show that if a, b, k and m are integers such that k1,m2, and ab(modm), then kakbk \geq 1 , m \geq 2 , \text { and } a \equiv b ( \bmod m ) , \text { then } k a \equiv k b (mod m).

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Use Fermat's little theorem to find 25120225 ^ { 1202 } mod 61 .

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find the sum and product of each of these pairs of numbers. Express your answer as a hexadecimal expansion. - (2 A)16,(BF)16( 2 \mathrm {~A} ) _ { 16 } , ( \mathrm { BF } ) _ { 16 }

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Use the Euclidean Algorithm to find gcd(580, 50).

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Here is a sample proof that contains an error. Explain why the proof is not correct. Theorem: If aba \mid b and bcb \mid c , then aca \mid c . Proof: Since ab,b=aka \mid b , b = a k . Since bc,c=bkb \mid c , c = b k . Therefore c=bk=(ak)k=ak2c = b k = ( a k ) k = a k ^ { 2 } . Therefore aca \mid c .

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refer to an 8-digit student id at a large university. The eighth digit is a check digit equal to the sum of the first seven digits modulo 7. -Find the check digit of the student id starting with 3179 822.

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Encrypt the message "just testing" using the function f(x) = (5x + 3) mod 26.

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Find the integer a such that a=89(mod19) and 9a9a = 89 ( \bmod 19 ) \text { and } - 9 \leq a \leq 9

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Find −88 mod 13.

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Prove or disprove: There exist two consecutive primes, each greater than 2.

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What does a 60-second stop watch read 82 seconds after it reads 27 seconds?

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Encrypt the message WATCH OUT using blocks of four letters and the transposition cipher based on the permutation of {1, 2, 3, 4} with σ(1) = 3, σ(2) = 4, σ(3) = 2, and σ(4) = 1.

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Convert (204)10 to base 2 .

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A message has been encrypted using the function f(x) = (x + 5) mod 26. If the message in coded form is JCFHY, decode the message.

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Convert (10011000011)2 to base 16 .

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Find the first five terms of the sequence of four-digit pseudorandom numbers generated by the middle square method starting with 9361.

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