Exam 8: Analytic Geometry in Two and Three Dimensions

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Find the vertex, the focus, and the directrix of the parabola. - x210x+8y+9=0\mathrm { x } ^ { 2 } - 10 \mathrm { x } + 8 \mathrm { y } + 9 = 0

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Solve the problem. -A rectangular board is 8 by 19 units. The foci of an ellipse are located to produce the largest area. A string is connected to the foci and pulled taut by a pencil in order to draw the ellipse. Find the length of the string.

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Match the polar equation with its graph. - r=41sinθr = \frac { 4 } { 1 - \sin \theta }

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Find the eccentricity of the ellipse. - 23x2+y2=2323 x ^ { 2 } + y ^ { 2 } = 23

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Find the standard form of the equation of the parabola. -Focus at (10,0)( 10,0 ) , directrix x=10x = - 10

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Find the vertices and foci of the conic section without axis rotation by analyzing the graph geometrically in the xy-plane. -The hyperbola xy=36x y = 36

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Write an equation for the illustrated plane. -Write an equation for the illustrated plane. -

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Find a polar equation for the conic described. -The hyperbola with a focus at the pole and transverse axis endpoints (4,π2)\left( 4 , \frac { \pi } { 2 } \right) and (8,3π2)\left( - 8 , \frac { 3 \pi } { 2 } \right)

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Determine the eccentricity, the type of conic, and the directrix. - r=36+8cosθr = \frac { 3 } { 6 + 8 \cos \theta }

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Match the polar equation with its graph. - r=1044sinθr = \frac { 10 } { 4 - 4 \sin \theta }

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Graph the parabola. - x=16(y4)2+4x = \frac { 1 } { 6 } ( y - 4 ) ^ { 2 } + 4  Graph the parabola. - x = \frac { 1 } { 6 } ( y - 4 ) ^ { 2 } + 4

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Find the center, vertices, and foci of the ellipse with the given equation. - (x+5)2100+(y1)264=1\frac { ( x + 5 ) ^ { 2 } } { 100 } + \frac { ( y - 1 ) ^ { 2 } } { 64 } = 1

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Graph the parabola. - x=14y2x = \frac { 1 } { 4 } y ^ { 2 }  Graph the parabola. - x = \frac { 1 } { 4 } y ^ { 2 }

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Use axis of rotation formulas for x and y to transform the quadratic equation to an equation in (u, v) coordinates with no cross-product term. - 2x2+23xy+4y28=02 x ^ { 2 } + 2 \sqrt { 3 } x y + 4 y ^ { 2 } - 8 = 0

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Solve the problem. -A comet follows the hyperbolic path described by x221y220=1\frac { x ^ { 2 } } { 21 } - \frac { y ^ { 2 } } { 20 } = 1 , where xx and yy are in millions. If the sun is the fc of the path, how close to the sun is the vertex of the path?  Solve the problem. -A comet follows the hyperbolic path described by  \frac { x ^ { 2 } } { 21 } - \frac { y ^ { 2 } } { 20 } = 1 , where  x  and  y  are in millions. If the sun is the fc of the path, how close to the sun is the vertex of the path?

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Determine the appropriate rotation formulas to use so that the new equation contains no xy-term. - x2+2xy+y28x+8y=0x ^ { 2 } + 2 x y + y ^ { 2 } - 8 x + 8 y = 0

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Determine the appropriate rotation formulas to use so that the new equation contains no xy-term. - 4x2+6xy+4y28x+8y=04 x ^ { 2 } + 6 x y + 4 y ^ { 2 } - 8 x + 8 y = 0

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Find an equation in standard form for the hyperbola that satisfies the given conditions. -Vertices at (±3,0)( \pm 3,0 ) , foci at (±9,0)( \pm 9,0 )

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Find the eccentricity of the hyperbola. - x216y2=1x ^ { 2 } - 16 y ^ { 2 } = 1

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Find the eccentricity of the hyperbola. - 8x29y2=728 x ^ { 2 } - 9 y ^ { 2 } = 72

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