Exam 8: Analytic Geometry in Two and Three Dimensions

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Write an equation for the illustrated plane. -Write an equation for the illustrated plane. -

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Graph the ellipse. - (x+2)216+(y3)24=1\frac{(x+2)^{2}}{16}+\frac{(y-3)^{2}}{4}=1  Graph the ellipse. - \frac{(x+2)^{2}}{16}+\frac{(y-3)^{2}}{4}=1

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Write an equation for the sphere with the given point as its center and the given number as its radius. - (9,4,5),6( 9,4,5 ) , 6

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Graph the parabola. - 8y=x28 y=-x^{2}  Graph the parabola. - 8 y=-x^{2}

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Solve the problem. - Solve the problem. -  A radio telescope has a parabolic surface. If it is  9 \mathrm {~m}  deep and  12 \mathrm {~m}  wide, how far is the focus from the vertex? A radio telescope has a parabolic surface. If it is 9 m9 \mathrm {~m} deep and 12 m12 \mathrm {~m} wide, how far is the focus from the vertex?

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Use the discriminant to decide whether the equation represents a parabola, an ellipse, or a hyperbola. - 3x2+6xy+3y22x+4y=03 x ^ { 2 } + 6 x y + 3 y ^ { 2 } - 2 x + 4 y = 0

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Find an equation in standard form for the ellipse that satisfies the given conditions. -An ellipse with center at origin, length of major axis 14 and yy -intercepts (0,±6)( 0 , \pm 6 )

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Solve the problem. - Solve the problem. -  A building has an entry the shape of a parabolic arch  98 \mathrm { ft }  high and  30 \mathrm { ft }  wide at the base. Find an equation for the parabola if the vertex is put at the origin of the coordinate system. A building has an entry the shape of a parabolic arch 98ft98 \mathrm { ft } high and 30ft30 \mathrm { ft } wide at the base. Find an equation for the parabola if the vertex is put at the origin of the coordinate system.

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Find the vertex, focus, directrix, and focal width of the parabola. - (x9)2=8(y+6)( x - 9 ) ^ { 2 } = - 8 ( y + 6 )

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Find an equation in standard form for the ellipse that satisfies the given conditions. -The vertical major axis is of length 8 , and the minor axis is of length 4 .

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Find the polar equation of the conic with focus at the pole, having the given properties. Identify the conic. -Directrix x=8x = - 8 , eccentricity 3

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Find the vertex, focus, directrix, and focal width of the parabola. - x=8y2x = 8 y ^ { 2 }

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Use the discriminant to decide whether the equation represents a parabola, an ellipse, or a hyperbola. - 4x22y2+2x+8y+2=04 x ^ { 2 } - 2 y ^ { 2 } + 2 x + 8 y + 2 = 0

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Find an equation in standard form for the hyperbola that satisfies the given conditions. -Foci at (0,±10)( 0 , \pm 10 ) , a conjugate axis with length 8

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Find the standard form of the equation of the parabola. -Vertex at (7,2)( - 7 , - 2 ) , opens to the left, focal width =14= 14

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Find the vertex, focus, directrix, and focal width of the parabola. - y2=12xy ^ { 2 } = - 12 x

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Solve the problem. -A domed ceiling is a parabolic surface. For the best lighting on the floor, a light source is to be placed at the focus of the surface. If 5 m5 \mathrm {~m} down from the top of the dome the ceiling is 23 m23 \mathrm {~m} wide, find the best location for the light source.

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Graph the parabola. - 8x=y2- 8 x = y ^ { 2 }  Graph the parabola. - - 8 x = y ^ { 2 }

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Find the polar equation of the conic with focus at the pole, having the given properties. Identify the conic. -Directrix y=9y = - 9 , eccentricity 3

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Graph the hyperbola. - x264y24=1\frac { x ^ { 2 } } { 64 } - \frac { y ^ { 2 } } { 4 } = 1  Graph the hyperbola. - \frac { x ^ { 2 } } { 64 } - \frac { y ^ { 2 } } { 4 } = 1

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