Exam 8: Analytic Geometry in Two and Three Dimensions

arrow
  • Select Tags
search iconSearch Question
flashcardsStudy Flashcards
  • Select Tags

Find an equation in standard form for the ellipse that satisfies the given conditions. -An ellipse with foci at (1,3)( - 1,3 ) and (5,3)( 5,3 ) ; major axis length of 10

(Multiple Choice)
4.8/5
(38)

Solve the problem. -Find the vector equation of the line through AA and BB . A=(7,6,7),B=(1,3,9),C=(6,8,7)A = ( 7,6 , - 7 ) , B = ( 1 , - 3 , - 9 ) , C = ( 6 , - 8,7 )

(Multiple Choice)
4.9/5
(31)

Graph the parabola. - y=23(x2)2+4y = \frac { 2 } { 3 } ( x - 2 ) ^ { 2 } + 4  Graph the parabola. - y = \frac { 2 } { 3 } ( x - 2 ) ^ { 2 } + 4

(Multiple Choice)
4.9/5
(31)

Graph the hyperbola. - y225x264=1\frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 64 } = 1  Graph the hyperbola. - \frac { y ^ { 2 } } { 25 } - \frac { x ^ { 2 } } { 64 } = 1

(Multiple Choice)
4.9/5
(34)

Use the discriminant to decide whether the equation represents a parabola, an ellipse, or a hyperbola. - 10y2+9x+10y+10=010 y ^ { 2 } + 9 x + 10 y + 10 = 0

(Multiple Choice)
4.8/5
(33)

Convert the equation to Cartesian form. - r=854cosθr = \frac { 8 } { 5 - 4 \cos \theta }

(Multiple Choice)
4.7/5
(29)

Find parametric equations for the line described below. -The line through the points P(1,1,4)P ( - 1 , - 1 , - 4 ) and Q(4,6,4)Q ( 4,6,4 )

(Multiple Choice)
4.9/5
(32)

Find the center, vertices, and foci of the ellipse with the given equation. - (x4)264+(y2)2100=1\frac { ( x - 4 ) ^ { 2 } } { 64 } + \frac { ( y - 2 ) ^ { 2 } } { 100 } = 1

(Multiple Choice)
4.8/5
(31)

Find an equation in standard form for the ellipse that satisfies the given conditions. -Major axis endpoints (0,±9)( 0 , \pm 9 ) , minor axis length 10

(Multiple Choice)
4.8/5
(40)

Graph the hyperbola. - (x+2)264(y2)236=1\frac { ( x + 2 ) ^ { 2 } } { 64 } - \frac { ( y - 2 ) ^ { 2 } } { 36 } = 1  Graph the hyperbola. - \frac { ( x + 2 ) ^ { 2 } } { 64 } - \frac { ( y - 2 ) ^ { 2 } } { 36 } = 1

(Multiple Choice)
4.9/5
(32)

Find an equation in standard form for the ellipse that satisfies the given conditions. -An ellipse with intercepts (±5,0)( \pm 5,0 ) and (0,±6)( 0 , \pm 6 ) , center at origin

(Multiple Choice)
4.8/5
(31)

Find an equation that matches the parabola's graph. -Find an equation that matches the parabola's graph. -

(Multiple Choice)
4.8/5
(40)

Solve the problem. -The roof of a building is in the shape of the hyperbola y2x2=66y ^ { 2 } - x ^ { 2 } = 66 , where xx and yy are in meters. Determine the distance, w, the outside walls are apart, if the height of each wall is 10 m10 \mathrm {~m} .  Solve the problem. -The roof of a building is in the shape of the hyperbola  y ^ { 2 } - x ^ { 2 } = 66 , where  x  and  y  are in meters. Determine the distance, w, the outside walls are apart, if the height of each wall is  10 \mathrm {~m} .

(Multiple Choice)
4.9/5
(45)

Graph the hyperbola. - (y+2)264(x+1)29=1\frac { ( y + 2 ) ^ { 2 } } { 64 } - \frac { ( x + 1 ) ^ { 2 } } { 9 } = 1  Graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 64 } - \frac { ( x + 1 ) ^ { 2 } } { 9 } = 1

(Multiple Choice)
4.8/5
(33)

Match the given graph with its equation. -Match the given graph with its equation. -

(Multiple Choice)
4.8/5
(35)

Graph the ellipse. - 9(x+4)2+4(y+6)2=369(x+4)^{2}+4(y+6)^{2}=36  Graph the ellipse. - 9(x+4)^{2}+4(y+6)^{2}=36

(Multiple Choice)
4.7/5
(39)

Match the given graph with its equation. -Match the given graph with its equation. -

(Multiple Choice)
4.9/5
(43)

Match the given graph with its equation. -Match the given graph with its equation. -

(Multiple Choice)
4.8/5
(33)

Find the standard form of the equation of the parabola. -Focus at (10,5)( 10,5 ) , directrix x=8x = 8

(Multiple Choice)
4.9/5
(42)

Find the standard form of the equation of the parabola. -Vertex at the origin, focus at (0,4)( 0,4 )

(Multiple Choice)
5.0/5
(48)
Showing 121 - 140 of 167
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)