Exam 4: Exponential and Logarithmic Functions

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Solve the equation for ss . - log(6 s8)=r4\log (6 \mathrm{~s}-8)=\mathrm{r}-4

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Write in logarithmic form. - 43=1644^{-3}=\frac{1}{64}

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Graph the function. - f(x)=(3x)f(x)=-\left(3^{x}\right)  Graph the function. - f(x)=-\left(3^{x}\right)

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Evaluate the expression. - log7.4300\log _{7.4}300

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Solve the problem. -In the formula A=Iekt,A\mathrm{A}=\mathrm{Ie}^{\mathrm{kt}}, \mathrm{A} is the amount of radioactive material remaining from an initial amount I at a given time tt and kk is a negative constant determined by the nature of the material. An artifact is discovered at a certain site. If it has 79%79 \% of the carbon-14 it originally contained, what is the approximate age of the artifact? (carbon-14 decays at the rate of 0.0125%0.0125 \% annually.) (Round to the nearest year.)

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Solve the problem. -The decay of 163mg163 \mathrm{mg} of an isotope is given by A(t)=163e0.014t\mathrm{A}(\mathrm{t})=163 \mathrm{e}^{-0.014 \mathrm{t}} , where t\mathrm{t} is time in years. Find the amount left after 13 years.

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Match the equation to the graph. -Match the equation to the graph. -

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Solve the equation. - log(x+9)=1logx\log (x+9)=1-\log x

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Write the logarithmic and exponential equations associated with the display. - f(x)=logxf(x)=\log x  Write the logarithmic and exponential equations associated with the display. - f(x)=\log x

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Write the word or phrase that best completes each statement or answers the question. - f(x)=axf(x)=a^{x}  Write the word or phrase that best completes each statement or answers the question. - f(x)=a^{x}     The graph of an exponential function with base a is given. Sketch the graph of  g(x)=a^{x+2} . Give the domain and range of  g . The graph of an exponential function with base a is given. Sketch the graph of g(x)=ax+2g(x)=a^{x+2} . Give the domain and range of gg .

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Solve the problem. -How long must $4700\$ 4700 be in a bank at 6%6 \% compounded annually to become $7067.06\$ 7067.06 ? (Use the function P(t)=P0ekt\mathrm{P}(\mathrm{t})=\mathrm{P}_{0} \mathrm{e}^{\mathrm{kt}} , where P0\mathrm{P}_{0} is the amount initially placed in savings, t\mathrm{t} is the time in years, and P(t)\mathrm{P}(\mathrm{t}) is the balance after time t\mathrm{t} . Round to the nearest year.)

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Solve the equation for ss . - 3r=log(6 s+6)3-\mathrm{r}=\log (6 \mathrm{~s}+6)

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