Exam 7: Estimation: Single Population

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An interval estimate is an interval that provides an upper and lower bound for a specific population parameter whose value is unknown.

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THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: A regional CPA firm conducted an audit for a discount chain.One part of the audit involved developing an estimate for the mean dollar error in total charges that occur during the checkout process.They wish to develop a 90% confidence interval estimate for the population mean.A simple random sample of n = 20 is selected,with the following data (in dollars): THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: A regional CPA firm conducted an audit for a discount chain.One part of the audit involved developing an estimate for the mean dollar error in total charges that occur during the checkout process.They wish to develop a 90% confidence interval estimate for the population mean.A simple random sample of n = 20 is selected,with the following data (in dollars):    -Develop a 90% confidence interval estimate for the population mean. -Develop a 90% confidence interval estimate for the population mean.

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Confidence intervals for the population proportion are centered on the sample proportion.

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As the confidence level for a confidence interval increases,the width of the interval also increases.

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Consider the following random sample from a normal population: 14,10,13,16,12,18,15,and 11.What is the 95% confidence interval for the population variance?

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The sample standard deviation s is an unbiased estimator of the population standard deviation σ.

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The bias of an estimator The bias of an estimator    is equal to E(    )- θ. is equal to E( The bias of an estimator    is equal to E(    )- θ. )- θ.

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When computing the confidence interval for the population proportion,the Student's t-distribution is used rather than the normal distribution.

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THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X1,X2,X3,and X4 be a random sample of observations from a population with mean μ and variance σ2.Consider the following two point estimators of μ: THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X<sub>1</sub>,X<sub>2</sub>,X<sub>3</sub>,and X<sub>4</sub> be a random sample of observations from a population with mean μ and variance σ<sup>2</sup>.Consider the following two point estimators of μ:    <sub>1</sub> = 0.10 X<sub>1</sub> + 0.20 X<sub>2</sub> + 0.40 X<sub>3</sub> + 0.30 X<sub>4</sub>,and    <sub>2</sub> = 0.25 X<sub>1</sub> + 0.25 X<sub>2</sub> + 0.30 X<sub>3</sub> + 0.20 X<sub>4</sub> -Raising in-state and out-of-state tuition is supposed to reduce the number of students in state supported universities.The registrar of a university wants to estimate the proportion P of students who are paying for out-of-state tuition on the installment plan (to later be compared with in-state installment plan payers).A random sample of 80 students who live out-of-state is taken and 50 of them pay tuition on the installment plan.Find a 99-percent confidence interval for P,based on these data. 1 = 0.10 X1 + 0.20 X2 + 0.40 X3 + 0.30 X4,and THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X<sub>1</sub>,X<sub>2</sub>,X<sub>3</sub>,and X<sub>4</sub> be a random sample of observations from a population with mean μ and variance σ<sup>2</sup>.Consider the following two point estimators of μ:    <sub>1</sub> = 0.10 X<sub>1</sub> + 0.20 X<sub>2</sub> + 0.40 X<sub>3</sub> + 0.30 X<sub>4</sub>,and    <sub>2</sub> = 0.25 X<sub>1</sub> + 0.25 X<sub>2</sub> + 0.30 X<sub>3</sub> + 0.20 X<sub>4</sub> -Raising in-state and out-of-state tuition is supposed to reduce the number of students in state supported universities.The registrar of a university wants to estimate the proportion P of students who are paying for out-of-state tuition on the installment plan (to later be compared with in-state installment plan payers).A random sample of 80 students who live out-of-state is taken and 50 of them pay tuition on the installment plan.Find a 99-percent confidence interval for P,based on these data. 2 = 0.25 X1 + 0.25 X2 + 0.30 X3 + 0.20 X4 -Raising in-state and out-of-state tuition is supposed to reduce the number of students in state supported universities.The registrar of a university wants to estimate the proportion P of students who are paying for out-of-state tuition on the installment plan (to later be compared with in-state installment plan payers).A random sample of 80 students who live out-of-state is taken and 50 of them pay tuition on the installment plan.Find a 99-percent confidence interval for P,based on these data.

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An unbiased estimator of a population parameter is an estimator whose variance is the same as the actual value of the population variance.

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THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: A furniture mover calculates the actual weight as a proportion of estimated weight for a sample of 31 recent jobs.The sample mean is 1.13 and the sample standard deviation is 0.16. -Assume that the population standard deviation is known to be 0.16.Calculate a 95% confidence interval for the population mean using the z table.

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The point estimator The point estimator    is said to be an unbiased estimator of θ if Var(    )= Var(θ). is said to be an unbiased estimator of θ if Var( The point estimator    is said to be an unbiased estimator of θ if Var(    )= Var(θ). )= Var(θ).

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In developing an interval estimate for a population mean,a sample of 40 observations was used.The interval estimate was 28.76 ± 1.48.Had the sample size been 160 instead of 40,the interval estimate would have been:

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A mother who is interested in the true proportion of R-rated movies shown on pay TV by a cable system randomly selects 98 listings and finds 14 of them are R-rated movies.In her report to the subcommittee she wants to be 98% confident that the true proportion will be in an interval which she states.She has asked you to assist her by preparing a 98% confidence interval based on the data she collected.What should she report?

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THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X1,X2,X3,and X4 be a random sample of observations from a population with mean μ and variance σ2.Consider the following two point estimators of μ: THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X<sub>1</sub>,X<sub>2</sub>,X<sub>3</sub>,and X<sub>4</sub> be a random sample of observations from a population with mean μ and variance σ<sup>2</sup>.Consider the following two point estimators of μ:    <sub>1</sub> = 0.10 X<sub>1</sub> + 0.20 X<sub>2</sub> + 0.40 X<sub>3</sub> + 0.30 X<sub>4</sub>,and    <sub>2</sub> = 0.25 X<sub>1</sub> + 0.25 X<sub>2</sub> + 0.30 X<sub>3</sub> + 0.20 X<sub>4</sub> -Which estimator is more efficient,(   <sub>1</sub>)or (   <sub>2</sub>)? Explain in detail. 1 = 0.10 X1 + 0.20 X2 + 0.40 X3 + 0.30 X4,and THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X<sub>1</sub>,X<sub>2</sub>,X<sub>3</sub>,and X<sub>4</sub> be a random sample of observations from a population with mean μ and variance σ<sup>2</sup>.Consider the following two point estimators of μ:    <sub>1</sub> = 0.10 X<sub>1</sub> + 0.20 X<sub>2</sub> + 0.40 X<sub>3</sub> + 0.30 X<sub>4</sub>,and    <sub>2</sub> = 0.25 X<sub>1</sub> + 0.25 X<sub>2</sub> + 0.30 X<sub>3</sub> + 0.20 X<sub>4</sub> -Which estimator is more efficient,(   <sub>1</sub>)or (   <sub>2</sub>)? Explain in detail. 2 = 0.25 X1 + 0.25 X2 + 0.30 X3 + 0.20 X4 -Which estimator is more efficient,( THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X<sub>1</sub>,X<sub>2</sub>,X<sub>3</sub>,and X<sub>4</sub> be a random sample of observations from a population with mean μ and variance σ<sup>2</sup>.Consider the following two point estimators of μ:    <sub>1</sub> = 0.10 X<sub>1</sub> + 0.20 X<sub>2</sub> + 0.40 X<sub>3</sub> + 0.30 X<sub>4</sub>,and    <sub>2</sub> = 0.25 X<sub>1</sub> + 0.25 X<sub>2</sub> + 0.30 X<sub>3</sub> + 0.20 X<sub>4</sub> -Which estimator is more efficient,(   <sub>1</sub>)or (   <sub>2</sub>)? Explain in detail. 1)or ( THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: Let X<sub>1</sub>,X<sub>2</sub>,X<sub>3</sub>,and X<sub>4</sub> be a random sample of observations from a population with mean μ and variance σ<sup>2</sup>.Consider the following two point estimators of μ:    <sub>1</sub> = 0.10 X<sub>1</sub> + 0.20 X<sub>2</sub> + 0.40 X<sub>3</sub> + 0.30 X<sub>4</sub>,and    <sub>2</sub> = 0.25 X<sub>1</sub> + 0.25 X<sub>2</sub> + 0.30 X<sub>3</sub> + 0.20 X<sub>4</sub> -Which estimator is more efficient,(   <sub>1</sub>)or (   <sub>2</sub>)? Explain in detail. 2)? Explain in detail.

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THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: A school bus driver records the time (in minutes)it takes to commute to school for six days.Those results are: 25,22,17,20,15,and 10.Assuming the population is normally distributed,develop a 90% confidence interval for the population mean. -What is the value of the sample standard deviation?

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The 95% confidence interval for the population proportion P given a sample size n = 300 and sample proportion The 95% confidence interval for the population proportion P given a sample size n = 300 and sample proportion   = 0.2933 is calculated as: = 0.2933 is calculated as:

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THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: From a random sample of 500 registered voters in Los Angeles,400 indicated that they would vote in favor of a proposed policy in an upcoming election. -Calculate the width of the 90% confidence interval estimate for the population proportion in favor of this policy.

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Which of the following statements is true?

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The upper limit of 90% confidence interval for the population proportion P,given a sample size n = 300 and sample proportion The upper limit of 90% confidence interval for the population proportion P,given a sample size n = 300 and sample proportion   = 0.1833 is equal to: = 0.1833 is equal to:

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