Exam 15: Chi-Squared Tests

For a chi-squared distributed random variable with 12 degrees of freedom and a level of significance of .05,the test statistics is 25.168.The chi-squared value from the table is 21.0261.These results will lead us to reject the null hypothesis.

The chi-squared distribution is used in:

What are the two critical factors in identifying the technique used when the data are nominal?

A cable company prepared four versions of a set of instructions for hooking up a TV.The company asked a sample of 1,600 people which one of the four forms was easiest to understand.In the sample,425 people preferred Form A,385 preferred Form B,375 preferred Form C,and 415 preferred Form D.At the 5% level of significance,can one conclude that in the population there is a preferred form?

To address whether two variables are related in a contingency table,the null hypothesis,H₀,says that

A test statistic that lies in the far right tail of the chi-squared distribution indicates you will ____________________ H₀.

If the expected frequency of a cell is less than 5,you should increase the significance level.

There are two critical factors in identifying the technique used when the data are nominal.The first is the problem objective.The second is the number of ____________________ that nominal variable can assume.

Contingency tables are used in:

In 2011,Brand A MP3 Players had 45% of the market,Brand B had 35%,and Brand C had 20%.This year the makers of brand C launched a heavy advertising campaign.A random sample of electronic stores shows that of 10,000 MP3 Players sold,4,350 were Brand A,3,450 were Brand B,and 2,200 were Brand C.Has the market changed? Test at α = .01.

For comparing two or more populations each having two or more categories,you can use which test(s)?

Student Absenteeism Consider a multinomial experiment involving n = 200 students of a large high school.The attendance department recorded the number of students who were absent during the weekdays.The null hypothesis to be tested is: H₀: p₁ = .10,p₂ = .25,p₃ = .30,p₄ = .20,p₅ = .15. -{Student Absenteeism Narrative} Test the hypothesis at the 5% level of significance with the following frequencies: (n = 100)

The chi-squared test of a(n)____________________ is used to determine whether there is enough evidence to say two nominal variables are related.

How do you calculate the expected frequency for one cell in a goodness-of-fit test?

You find the expected value for each cell in a chi-squared test for a contingency table by multiplying the ____________________ total by the ____________________ total and dividing by the sample size,n.

Conduct a test to determine whether the two classifications A and B are independent,using the data in the accompanying table and α = .05.

When k = 2 the ____________________ experiment is identical to the ____________________ experiment.

To analyze the relationship between two nominal variables,use a(n)____________________ test of a(n)____________________.

The rule of ____________________ states that in order to conduct the chi-squared goodness-of-fit test,the expected value for each cell must be ____________________ or more.

The chi-squared goodness-of-fit test compares the ____________________ frequencies in the table to the ____________________ frequencies based on the null hypothesis.