Exam 15: Chemical Equilibrium

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The Kp for the reaction below is 1.49 × 108 at 100 °C: CO (g) + Cl2 (g) -COCl2 (g) In an equilibrium mixture of the three gases, PCO = PCl2 = 8.60 × 10- 4 atm. The partial pressure of the product, phosgene (COCl2), is atm.

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At 200 °C, the equilibrium constant (Kp) for the reaction below is 2.40 × 103. 2NO (g) At 200 °C, the equilibrium constant (K<sub>p</sub>) for the reaction below is 2.40 × 10<sup>3</sup>. 2NO (g)   N<sub>2 </sub>(g) + O<sub>2</sub><sub> </sub>(g) A closed vessel is charged with 36.1 atm of NO. At equilibrium, the partial pressure of O<sub>2 </sub>is Atm) N2 (g) + O2 (g) A closed vessel is charged with 36.1 atm of NO. At equilibrium, the partial pressure of O2 is Atm)

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In an exothermic equilibrium reaction, increasing the reaction temperature favors the formation of reactants.

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The number obtained by substituting starting reactant and product concentrations into an equilibrium- constant expression is known as the .

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In the coal- gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) In the coal- gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H<sub>2</sub>O (g)   CO<sub>2 </sub>(g) + H<sub>2</sub><sub> </sub>(g) In an experiment, 0.35 mol of CO and 0.40 mol of H<sub>2</sub>O were placed in a 1.00- L reaction vessel. At equilibrium, there were 0.19 mol of CO remaining. K<sub>eq</sub><sub> </sub>at the temperature of the experiment is ) CO2 (g) + H2 (g) In an experiment, 0.35 mol of CO and 0.40 mol of H2O were placed in a 1.00- L reaction vessel. At equilibrium, there were 0.19 mol of CO remaining. Keq at the temperature of the experiment is )

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The equilibrium constant for the gas phase reaction N2 (g) + 3H2 (g) The equilibrium constant for the gas phase reaction N<sub>2 </sub>(g) + 3H<sub>2</sub><sub> </sub>(g)   2NH<sub>3</sub><sub> </sub>(g) Is K<sub>eq </sub>= 4.34 × 10<sup>- </sup><sup>3 </sup>at 300 °C. At equilibrium, _ _. 2NH3 (g) Is Keq = 4.34 × 10- 3 at 300 °C. At equilibrium, _ _.

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A sealed 1.0 L flask is charged with 0.500 mol of I2 and 0.500 mol of Br2. An equilibrium reaction ensues: I2 (g) + Br2 (g) A sealed 1.0 L flask is charged with 0.500 mol of I<sub>2</sub><sub> </sub>and 0.500 mol of Br<sub>2</sub>. An equilibrium reaction ensues: I<sub>2 </sub>(g) + Br<sub>2</sub><sub> </sub>(g)   2IBr (g) When the container contents achieve equilibrium, the flask contains 0.84 mol of IBr. The value of K<sub>eq</sub><sub> </sub>is _ . 2IBr (g) When the container contents achieve equilibrium, the flask contains 0.84 mol of IBr. The value of Keq is _ .

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A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine: 2HI (g) A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine: 2HI (g)   H<sub>2</sub>(g) + I<sub>2</sub>(g) <sup>When the system comes to equilibrium at 425 °C, P</sup><sub>HI </sub><sup>= </sup><sup>0.708 atm, and </sup><sup>P</sup>H<sub>2 </sub><sup>= </sup><sup>P</sup>I<sub>2</sub> = 0)0960 atm. The value of K<sub>p </sub>at this temperature is . H2(g) + I2(g) When the system comes to equilibrium at 425 °C, PHI = 0.708 atm, and PH2 = PI2 = 0)0960 atm. The value of Kp at this temperature is .

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At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H2 (g) + Br2 (g) At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H<sub>2 </sub>(g) + Br<sub>2</sub><sub> </sub>(g)   2HBr (g) A mixture of 0.682 mol of H<sub>2</sub><sub> </sub>and 0.440 mol of Br<sub>2</sub><sub> </sub>is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.566 mol of H<sub>2</sub><sub> </sub>present. At equilibrium, there are Mol of Br<sub>2 </sub>present in the reaction vessel. 2HBr (g) A mixture of 0.682 mol of H2 and 0.440 mol of Br2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.566 mol of H2 present. At equilibrium, there are Mol of Br2 present in the reaction vessel.

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The value of Keq for the equilibrium H2 (g) + I2 (g) The value of K<sub>eq </sub>for the equilibrium H<sub>2 </sub>(g) + I<sub>2</sub><sub> </sub>(g)   2 HI (g) Is 794 at 25 °C. At this temperature, what is the value of K<sub>eq </sub>for the equilibrium below? HI (g) 1/2 H<sub>2 </sub>(g) + 1/2 I<sub>2</sub><sub> </sub>(g)  2 HI (g) Is 794 at 25 °C. At this temperature, what is the value of Keq for the equilibrium below? HI (g) 1/2 H2 (g) + 1/2 I2 (g) The value of K<sub>eq </sub>for the equilibrium H<sub>2 </sub>(g) + I<sub>2</sub><sub> </sub>(g)   2 HI (g) Is 794 at 25 °C. At this temperature, what is the value of K<sub>eq </sub>for the equilibrium below? HI (g) 1/2 H<sub>2 </sub>(g) + 1/2 I<sub>2</sub><sub> </sub>(g)

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The equilibrium- constant expression depends on the of the reaction.

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Exactly 3.5 moles if N2O4 is placed in an empty 2.0- L container and allowed to reach equilibrium described by the equation N2O4 (g) "2NO2 (g) If at equilibrium the N2O4 is 25% dissociated, what is the value of the equilibrium constant for the reaction?

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For the endothermic reaction CaCO3 (s) For the endothermic reaction CaCO<sub>3</sub><sub> </sub>(s)   CaO (s) + CO<sub>2</sub><sub> </sub>(g) Le Cha<sup>^</sup>telier's principle predicts that _ will result in an increase in the number of moles of CO<sub>2</sub>. CaO (s) + CO2 (g) Le Cha^telier's principle predicts that _ will result in an increase in the number of moles of CO2.

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Consider the following reaction at equilibrium: 2NH3 (g) Consider the following reaction at equilibrium: 2NH<sub>3</sub><sub> </sub>(g)   N<sub>2 </sub>(g) + 3H<sub>2</sub><sub> </sub>(g) OH° = +92.4 kJ Le Cha<sup>^</sup>telier's principle predicts that adding N<sub>2</sub><sub> </sub>(g) to the system at equilibrium will result in N2 (g) + 3H2 (g) OH° = +92.4 kJ Le Cha^telier's principle predicts that adding N2 (g) to the system at equilibrium will result in

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The Keq for the equilibrium below is 7.52 × 10- 2 at 480 °C. The K<sub>eq </sub>for the equilibrium below is 7.52 × 10<sup>- </sup><sup>2 </sup>at 480 °C.    The K<sub>eq </sub>for the equilibrium below is 7.52 × 10<sup>- </sup><sup>2 </sup>at 480 °C.

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The effect of a catalyst on an equilibrium is to .

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The Keq for the equilibrium below is 0.112 at 700 °C. SO2 (g) + 1 O2 The K<sub>eq</sub><sub> </sub>for the equilibrium below is 0.112 at 700 °C. SO<sub>2 </sub>(g) + <sup> </sup><sup>1</sup><sup> </sup>O<sub>2</sub>

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At constant temperature, reducing the volume of a gaseous equilibrium mixture causes the reaction to shift in the direction that increases the number of moles of gas in the system.

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Le Chatelier's principle states that if a system at equilibrium is disturbed, the equilibrium will shift to minimize the disturbance.

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In which of the following reactions would increasing pressure at constant temperature not change the concentrations of reactants and products, based on Le Cha^telier's principle?

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