Exam 12: Experimental Design and Analysis of Variance
Exam 1: An Introduction to Business Statistics and Analytics98 Questions
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Exam 3: Descriptive Statistics and Analytics: Numerical Methods145 Questions
Exam 4: Probability and Probability Models150 Questions
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Exam 6: Discrete Random Variables150 Questions
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Exam 8: Sampling Distributions111 Questions
Exam 9: Confidence Intervals149 Questions
Exam 10: Hypothesis Testing150 Questions
Exam 11: Statistical Inferences Based on Two Samples140 Questions
Exam 12: Experimental Design and Analysis of Variance132 Questions
Exam 13: Chi-Square Tests120 Questions
Exam 14: Simple Linear Regression Analysis147 Questions
Exam 15: Multiple Regression and Model Building85 Questions
Exam 16: Predictive Analytics Ii: Logistic Regression, Discriminate Analysis,101 Questions
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Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 treatments.
Determine the degrees of freedom for error.

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(Short Answer)
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Correct Answer:
df error = 15
(4 − 1)(6 − 1) = 15
ANOVA table
Post hoc analysis
Tukey simultaneous comparison t-values
The Excel/MegaStat output given above summarizes the results of a one-way analysis of variance in an attempt to compare the performance characteristics of four brands of vacuum cleaners. The response variable is the amount of time it takes to clean a specific size room with a specific amount of dirt.
Use the information above and determine a Tukey simultaneous 95 percent confidence interval for μ1 − μ2. The mean and sample sizes for brand 1 and brand 2 are as follows:
= 2.95,
= 2.28, n1 = 4, and n2 = 5.




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Correct Answer:
[.035, 1.305]
[(2.95 − 2.28) ± (4.11/ )(
)] = [.67 ± (2.9066)(.2185)] = [.67 ± .635] = [.035, 1.305]
Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 treatments.
Test H0: there is no difference between treatment effects at α = .05.

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Correct Answer:
Since our calculated F value (1.91) is less than the critical F value (2.422) we cannot reject the null hypothesis; there is no evidence of difference between treatments. =
= 1.91
F = 1.91
F.05,5,45 = 2.422
1.91 < 2.422, so do not reject the null hypothesis.
In one-way ANOVA, the numerator degrees of freedom equals the number of samples being compared.
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Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 treatments.
What is the calculated F statistic for treatment?

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In a one-way analysis of variance with three treatments, each with five measurements, in which a completely randomized design is used, what are the degrees of freedom for error?
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________ refers to applying a treatment to more than one experimental unit.
(Multiple Choice)
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A company that fills one-gallon containers of water has four machines. The quality control manager needs to determine whether the average fill for these machines is the same. For a sample of 19 one-gallon containers, we have the following data of fill measures (x) in quarts.
Machine 1 Machine 2 Machine 3 Machine 4
N 4 6 5 4
(3 - 2) ± 4.53
= (-2.377, 4.377) 4.03 4.0017 3.974 4.005
S 0.0183 0.0117 0.0182 0.0129
And the following partial ANOVA table.
Determine the degrees of freedom for the treatment, error, and total, and state the critical value of the F statistic at α = .05.


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In a completely randomized ANOVA, with other things equal, as the sample means get closer to each other, the probability of rejecting the null hypothesis
(Multiple Choice)
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When we compute 100(1 − α) confidence intervals, the value of α is called the
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ANOVA table
Post hoc analysis
Tukey simultaneous comparison t-values
The Excel/MegaStat output given above summarizes the results of a one-way analysis of variance in an attempt to compare the performance characteristics of four brands of vacuum cleaners. The response variable is the amount of time it takes to clean a specific size room with a specific amount of dirt.
At a significance level of .05, the null hypothesis for the ANOVA F test is rejected. Analysis of the Tukey simultaneous confidence intervals shows that at the significance level (experimentwise) of .05, we would conclude that


(Multiple Choice)
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Consider the following partial analysis of variance table from a randomized block design with 6 blocks and 4 treatments.
What is the treatment mean square?

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The ________ units are the entities (objects, people, etc.) to which the treatments are assigned.
(Multiple Choice)
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Consider the randomized block design with 4 blocks and 3 treatments given above. What is the value of the F statistic for blocks?

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Consider the following partial analysis of variance table from a randomized block design with 10 blocks and 6 treatments.
What is the treatment mean square?

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Looking at four different diets, a researcher randomly assigned 20 equally overweight individuals into each of the four diets. What are the degrees of freedom for the individual confidence intervals?
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Find a Tukey simultaneous 95 percent confidence interval for μ1 − μ2, where
= 33.98,
= 36.56, and MSE = .669. There were 15 observations total and 3 treatments. Assume that the number of observations in each treatment is equal.


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In one-way ANOVA, the total sum of squares is equal to ________.
(Multiple Choice)
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When computing individual confidence intervals using the t statistic, for all possible pairwise comparisons of means, the experimentwise error rate will be
(Multiple Choice)
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A vitamin-water manufacturer wants to compare the effects on sales of three water colors: green, blue, and red. Four regions are selected for the test, with the following ANOVA results.
Compute the mean square and F to test the null hypothesis that there is no interaction at α = .01.

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