Exam 5: Analytic Trigonometry

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Which of the following is equivalent to the given expression? cos2x1+sinx\frac { \cos ^ { 2 } x } { 1 + \sin x }

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Find the exact solutions of the given equation in the interval [0, 2 π\pi ). cos2x+3cosx+2=0\cos 2 x + 3 \cos x + 2 = 0

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Find the exact value of the given expression using a sum or difference formula. sin285\sin 285 ^ { \circ }

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Solve the following equation. 9cot2x3=09 \cot ^ { 2 } x - 3 = 0

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A Ferris wheel is built such that the height h (in feet) above the ground of a seat on the wheel at time t (in seconds) can be modeled by h(t)=67+54sin(π18tπ2)h ( t ) = 67 + 54 \sin \left( \frac { \pi } { 18 } t - \frac { \pi } { 2 } \right) .The wheel makes one revolution every 36 seconds and the ride begins when t = 0.During the first 36 seconds of the ride, when will a person, who starts at the bottom of the Ferris wheel, be 67 feet above the ground?

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Use the trigonometric substitution to rewrite the algebraic expression as a trigonometric function of θ\theta , where 0<θ<π20 < \theta < \frac { \pi } { 2 } . 369x2,x=2cosθ\sqrt { 36 - 9 x ^ { 2 } } , x = 2 \cos \theta

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Use the cofunction identities to evaluate the expression without using a calculator. ​ Tan273° + cot214° - sec276° - csc217° ​

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The mach number M of an airplane is the ratio of its speed to the speed of sound.When an airplane travels faster than the speed of sound, the sound waves form a cone behind the airplane (see figure).The mach number is related to the apex angle θ\theta of the cone by sin(θ/5)=1/M\sin ( \theta / 5 ) = 1 / M .  The mach number M of an airplane is the ratio of its speed to the speed of sound.When an airplane travels faster than the speed of sound, the sound waves form a cone behind the airplane (see figure).The mach number is related to the apex angle  \theta   of the cone by  \sin ( \theta / 5 ) = 1 / M  .       Rewrite the equation in terms of  \theta .   Rewrite the equation in terms of θ\theta .

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The monthly sales S (in hundreds of units) of baseball equipment for an Internet sporting goods site are approximated by S=55.737.5cosπt6S = 55.7 - 37.5 \cos \frac { \pi t } { 6 } where t is the time (in months), with t = 1 corresponding to January.Determine the months when sales exceed 7700 units at any time during the month.

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Evaluate the following expression.(x ≠ π/2+πn, where n is a whole number) ​ 2 cos x + 2 sin x tan x ​

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Find all solutions of the following equation in the interval [0, 2 π\pi ). 5sec2x5=05 \sec ^ { 2 } x - 5 = 0

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Use the trigonometric substitution to rewrite the algebraic expression as a trigonometric function of θ\theta , where π2<θ<π2- \frac { \pi } { 2 } < \theta < \frac { \pi } { 2 } .Then find sin θ\theta and cos θ\theta . 33=819x2,x=3cosθ3 \sqrt { 3 } = \sqrt { 81 - 9 x ^ { 2 } } , x = 3 \cos \theta

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Simplify the expression algebraically. cos(7x+4y)cos(7x4y)\cos ( 7 x + 4 y ) \cos ( 7 x - 4 y )

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Simplify the following expression algebraically. 6tan(π+θ)6 \tan ( \pi + \theta )

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Use the trigonometric substitution to rewrite the algebraic expression as a trigonometric function of θ\theta , where 0<x<π20 < x < \frac { \pi } { 2 } . 25x2+36,5x=6tanθ\sqrt { 25 x ^ { 2 } + 36 } , 5 x = 6 \tan \theta

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Use the sum-to-product formulas to write the given expression as a product. sin5θsin3θ\sin 5 \theta - \sin 3 \theta

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A weight is attached to a spring suspended vertically from a ceiling.When a driving force is applied to the system, the weight moves vertically from its equilibrium position, and this motion is modeled by y=18sin2t+16cos2ty = \frac { 1 } { 8 } \sin 2 t + \frac { 1 } { 6 } \cos 2 t where y is the distance from equilibrium (in feet) and t is the time (in seconds). Find the amplitude of the oscillations of the weight.

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Solve the following equation. Secx - 2 = 0

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Use the sum-to-product formulas to rewrite the sum or difference as a product. sin9θ+sin7θ\sin 9 \theta + \sin 7 \theta

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Find the rate of change of the function f(x)=x+cosxf ( x ) = - x + \cos x .

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