Exam 5: Inverse, Exponential, and Logarithmic Functions

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Solve the equation. Round to the nearest thousandth. - e4xe4x=e4e ^ { 4 x } e ^ { 4 x } = e ^ { 4 }

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Solve the equation. Round to the nearest thousandth. - 15(3x)=2315 ( 3 - x ) = 23

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Use the definition of inverses to determine whether f and g are inverses. - f(x)=1x+6,g(x)=6x+1xf ( x ) = \frac { 1 } { x + 6 } , \quad g ( x ) = \frac { 6 x + 1 } { x }

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Provide an appropriate response. -Use the properties of exponents to write the function of the form f(t)=kat\mathrm { f } ( \mathrm { t } ) = \mathrm { ka } ^ { \mathrm { t } } , where k\mathrm { k } is a constant. f(t)=33t+2f ( t ) = 3 ^ { 3 t + 2 }

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Find the value. Give an approximation to four decimal places. - ln(9818)\ln \left( \frac { 98 } { 18 } \right)

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Solve the equation and express the solution in exact form. - log2x2=(log2x)2\log _ { 2 } x ^ { 2 } = \left( \log _ { 2 } x \right) ^ { 2 }

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Use the graph of f to sketch a graph of the inverse of f using a dashed curve. -Use the graph of f to sketch a graph of the inverse of f using a dashed curve. -

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Use properties of logarithms to evaluate the expression. -Let u=lna\mathrm { u } = \ln \mathrm { a } and v=lnb\mathrm { v } = \ln \mathrm { b } . Write the following expression in terms of u\mathrm { u } and v\mathrm { v } without using the funct lna5b73\ln \sqrt [ 3 ] { \frac { a ^ { 5 } } { b ^ { 7 } } }

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Choose the one alternative that best completes the statement or answers the question. -Many states have passed laws against smoking in public places since January. The total number of states, N\mathrm { N } , that have passed a no smoking law, t\mathrm { t } months after January is given by the function N(t)=501+19e0.7t\mathrm { N } ( \mathrm { t } ) = \frac { 50 } { 1 + 19 \mathrm { e } ^ { - 0.7 \mathrm { t } } } . How many states had passed a law in January? Round to the nearest thousandth.

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Match the function with its graph. - f(x)=log2xf ( x ) = \log _ { 2 } x

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Solve the problem. - p(t)=2346e0.003t\mathrm { p } ( \mathrm { t } ) = 2346 \mathrm { e } ^ { 0.003 \mathrm { t } } , where t is the number of years. Use this formula to calculate the population after 10 years.

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Match the function with its graph. - f(x)=log2(1x)f ( x ) = \log _ { 2 } \left( \frac { 1 } { x } \right)

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Solve the equation and express the solution in exact form. - lnexlne5=lne8\ln \mathrm { e } ^ { \mathrm { x } } - \ln \mathrm { e } ^ { 5 } = \ln \mathrm { e } ^ { 8 }

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Decide whether the given functions are inverses. - f=\{(5,13),(4,0),(0,20),(13,5)\} g=\{(13,5),(0,4),(20,0),(5,13)\}

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Use properties of logarithms to evaluate the expression. -If f(x)=lnx\mathrm { f } ( \mathrm { x } ) = \ln \mathrm { x } , find f(e18ln11)\mathrm { f } \left( \mathrm { e } ^ { 18 \ln 11 } \right)

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Find the value. Give an approximation to four decimal places. - log(682249)\log \left( \frac { 682 } { 249 } \right)

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Use properties of logarithms to evaluate the expression. -Let u=lna\mathrm { u } = \ln \mathrm { a } and v=lnb\mathrm { v } = \ln \mathrm { b } . Write the following expression in terms of u\mathrm { u } and v\mathrm { v } without using the funct ln(ab45)\ln \left( \sqrt [ 5 ] { a b ^ { 4 } } \right)

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Solve the problem. -The population growth of an animal species is described by F(t)=400log(2t+3)F ( t ) = 400 \log ( 2 t + 3 ) where t is measured in months. Find the population of this species in an area 6 months after the species is Introduced.

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Solve the equation. Round to the nearest thousandth. - 4x=124 ^ { x } = 12

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Solve the equation. - (5)x+5=25x( \sqrt { 5 } ) ^ { x + 5 } = 25 ^ { x }

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