Exam 9: Analytic Geometry

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Graph the equation. - (y1)2=7(x+2)(y-1)^{2}=-7(x+2)  Graph the equation. - (y-1)^{2}=-7(x+2)

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Solve the problem. -An experimental model for a suspension bridge is built in the shape of a parabolic arch. In one section, cable runs from the top of one tower down to the roadway, just touching it there, and up again to the top of a second Tower. The towers are both 12.25 inches tall and stand 70 inches apart. At some point along the road from the Lowest point of the cable, the cable is 1.96 inches above the roadway. Find the distance between that point and The base of the nearest tower.

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Identify the equation without completing the square. - y24x2+8x+4y+3=0y ^ { 2 } - 4 x ^ { 2 } + 8 x + 4 y + 3 = 0

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Solve the problem. -A reflecting telescope contains a mirror shaped like a paraboloid of revolution. If the mirror is 24 inches across at its opening and is 4 feet deep, where will the light be concentrated?

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Graph the curve whose parametric equations are given. - x=2t,y=t+5;2t3x=2 t, y=t+5 ;-2 \leq t \leq 3  Graph the curve whose parametric equations are given. - x=2 t, y=t+5 ;-2 \leq t \leq 3

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Find the center, foci, and vertices of the ellipse. - (x1)236+(y+2)29=1\frac { ( x - 1 ) ^ { 2 } } { 36 } + \frac { ( y + 2 ) ^ { 2 } } { 9 } = 1

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Graph the hyperbola. - 25x2=9y2+22525 x^{2}=9 y^{2}+225  Graph the hyperbola. - 25 x^{2}=9 y^{2}+225

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Find an equation for the ellipse described. Graph the equation. -Foci at (4,1)( - 4 , - 1 ) and (2,1)( 2 , - 1 ) ; length of major axis is 10  Find an equation for the ellipse described. Graph the equation. -Foci at  ( - 4 , - 1 )  and  ( 2 , - 1 ) ; length of major axis is 10

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Convert the polar equation to a rectangular equation. - r=222cosθr = \frac { 2 } { 2 - 2 \cos \theta }

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Graph the hyperbola. - 25y2=9x2+22525 y^{2}=9 x^{2}+225  Graph the hyperbola. - 25 y^{2}=9 x^{2}+225

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Solve the problem. -A bridge is built in the shape of a semielliptical arch. It has a span of 94 feet. The height of the arch 30 feet from the center is to be 6 feet. Find the height of the arch at its center.

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Find an equation for the parabola described. -Vertex at (3, -4); focus at (3, -6) A) (x3)2=8(y+4)( x - 3 ) ^ { 2 } = 8 ( y + 4 ) B) (x3)2=8(y+4)( x - 3 ) ^ { 2 } = - 8 ( y + 4 ) C) (y4)2=12(x+3)( y - 4 ) ^ { 2 } = - 12 ( x + 3 ) D) (y4)2=12(x+3)( y - 4 ) ^ { 2 } = 12 ( x + 3 )

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Graph the curve whose parametric equations are given. - x=t3+1,y=t310;2t2x=t^{3}+1, y=t^{3}-10 ;-2 \leq t \leq 2  Graph the curve whose parametric equations are given. - x=t^{3}+1, y=t^{3}-10 ;-2 \leq t \leq 2

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Identify the equation without applying a rotation of axes. - 3x2+8xy+2y2+3x+2y+10=03 x ^ { 2 } + 8 x y + 2 y ^ { 2 } + 3 x + 2 y + 10 = 0

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Graph the ellipse and locate the foci. - x29+y216=1\frac{x^{2}}{9}+\frac{y^{2}}{16}=1  Graph the ellipse and locate the foci. - \frac{x^{2}}{9}+\frac{y^{2}}{16}=1

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Find a rectangular equation for the plane curve defined by the parametric equations. - x=5cost,y=2sint;0t2πx = 5 \cos t , y = - 2 \sin t ; 0 \leq t \leq 2 \pi

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Solve the problem. -A bridge is built in the shape of a parabolic arch. The bridge arch has a span of 174 feet and a maximum height of 30 feet. Find the height of the arch at 15 feet from its center.

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Graph the ellipse and locate the foci. - 4x2+16y2=644 x^{2}+16 y^{2}=64  Graph the ellipse and locate the foci. - 4 x^{2}+16 y^{2}=64

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Solve the problem. -A searchlight is shaped like a paraboloid of revolution. If the light source is located 5 feet from the base along the axis of symmetry and the opening is 8 feet across, how deep should the searchlight be?

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Graph the curve whose parametric equations are given. - :x=7t,y=7-7t;\leqt\leq :x=t,y=;\leqt\leq :x=-8,y=t-3;-4\leqt\leq4 :x=t-5,y=t+2;-4\leqt\leq7

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