Exam 9: Analytic Geometry

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Find an equation of the parabola described and state the two points that define the latus rectum. -Focus at (0, 4); directrix the line y = -4 A) y2=4xy ^ { 2 } = 4 x ; latus rectum: (9,2)( 9,2 ) and (9,2)( - 9,2 ) B) x2=4yx ^ { 2 } = 4 y ; latus rectum: (2,4)( 2,4 ) and (2,4)( - 2,4 ) C) x2=16yx ^ { 2 } = 16 y ; latus rectum: (8,4)( 8,4 ) and (8,4)( - 8,4 ) D) x2=16yx ^ { 2 } = 16 y ; latus rectum: (4,8)( 4,8 ) and (4,8)( - 4,8 )

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Find a polar equation for the conic. A focus is at the pole. - e=1\mathrm { e } = 1 ; directrix is parallel to the polar axis 1 above the pole

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Solve the problem. -A spotlight has a parabolic cross section that is 6 ft wide at the opening and 2.5 ft deep at the vertex. How far from the vertex is the focus? Round answer to two decimal places.

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Identify the equation without completing the square. - 2x23y2+3x+2y+2=02 x ^ { 2 } - 3 y ^ { 2 } + 3 x + 2 y + 2 = 0

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Graph the curve whose parametric equations are given. - x=sect,y=tant;π2<t<π2x = - \sec t , y = \tan t ; - \frac { \pi } { 2 } < t < \frac { \pi } { 2 }  Graph the curve whose parametric equations are given. - x = - \sec t , y = \tan t ; - \frac { \pi } { 2 } < t < \frac { \pi } { 2 }

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Find the asymptotes of the hyperbola. - y2x2=9y ^ { 2 } - x ^ { 2 } = 9

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Find a rectangular equation for the plane curve defined by the parametric equations. - x=2t1,y=t2+4;4t4x = 2 t - 1 , y = t ^ { 2 } + 4 ; - 4 \leq t \leq 4

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Rotate the axes so that the new equation contains no xy-term. Graph the new equation. - 24xy7y2+36=024 x y-7 y^{2}+36=0  Rotate the axes so that the new equation contains no xy-term. Graph the new equation. - 24 x y-7 y^{2}+36=0

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Solve the problem. - y216x24=1\frac { y ^ { 2 } } { 16 } - \frac { x ^ { 2 } } { 4 } = 1

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Identify the conic that the polar equation represents. Also, give the position of the directrix. - r=563sinθr = \frac { 5 } { 6 - 3 \sin \theta }

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Graph the equation. - (x+2)2=8(y1)(x+2)^{2}=8(y-1)  Graph the equation. - (x+2)^{2}=8(y-1)

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Solve the problem. -A satellite dish is shaped like a paraboloid of revolution. The signals that emanate from a satellite strike the surface of the dish and are reflected to a single point, where the receiver is located. If the dish is 8 feet across at its opening and is 2 feet deep at its center, at what position should the receiver be placed?

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Find a polar equation for the conic. A focus is at the pole. - e=5e = 5 ; directrix is perpendicular to the polar axis 3 to the right of the pole

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Graph the curve whose parametric equations are given. - x=2tant,y=4sect;0t2πx=2 \tan t, y=4 \sec t ; 0 \leq t \leq 2 \pi  Graph the curve whose parametric equations are given. - x=2 \tan t, y=4 \sec t ; 0 \leq t \leq 2 \pi

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Find an equation for the hyperbola described. -center at (9,4)( 9,4 ) ; focus at (7,4)( 7,4 ) ; vertex at (8,4)( 8,4 )

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Find the vertex, focus, and directrix of the parabola with the given equation. - (y4)2=8(x+2)(y-4)^{2}=-8(x+2)

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Graph the hyperbola. -Two recording devices are set 2,800 feet apart, with the device at point A to the west of the device at point B. At a point on a line between the devices, 400 feet from point B, a small amount of explosive is detonated. The Recording devices record the time the sound reaches each one. How far directly north of site B should a second Explosion be done so that the measured time difference recorded by the devices is the same as that for the first Detonation?

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Name the conic. -Name the conic. -

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Find the vertex, focus, and directrix of the parabola. - y2=12xy^{2}=-12 x  Find the vertex, focus, and directrix of the parabola. - y^{2}=-12 x     A)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(-3,0) \\ \text { directrix: } x=3 \end{array}      B)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(3,0) \\ \text { directrix: } x=-3 \end{array}     C) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3     D) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3       A) vertex: (0,0) focus: (-3,0) directrix: x=3  Find the vertex, focus, and directrix of the parabola. - y^{2}=-12 x     A)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(-3,0) \\ \text { directrix: } x=3 \end{array}      B)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(3,0) \\ \text { directrix: } x=-3 \end{array}     C) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3     D) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3       B) vertex: (0,0) focus: (3,0) directrix: x=-3  Find the vertex, focus, and directrix of the parabola. - y^{2}=-12 x     A)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(-3,0) \\ \text { directrix: } x=3 \end{array}      B)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(3,0) \\ \text { directrix: } x=-3 \end{array}     C) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3     D) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3       C) vertex: (0,0)( 0,0 ) focus: (0,3)( 0 , - 3 ) directrix: y=3y = 3 11ed81f4_181c_1451_a8e7_855e330b9a6b_TB7697_11 D) vertex: (0,0)( 0,0 ) focus: (0,3)( 0 , - 3 ) directrix: y=3y = 3  Find the vertex, focus, and directrix of the parabola. - y^{2}=-12 x     A)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(-3,0) \\ \text { directrix: } x=3 \end{array}      B)  \begin{array}{l} \text { vertex: }(0,0) \\ \text { focus: }(3,0) \\ \text { directrix: } x=-3 \end{array}     C) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3     D) vertex:  ( 0,0 )  focus:  ( 0 , - 3 )  directrix:  y = 3

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Find the asymptotes of the hyperbola. - (x2)24(y1)225=1\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 25 } = 1

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