Exam 9: Analytic Geometry

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Graph the equation. - x2=12yx^{2}=12 y  Graph the equation. - x^{2}=12 y     A)    B)    C)    D)    A)  Graph the equation. - x^{2}=12 y     A)    B)    C)    D)    B)  Graph the equation. - x^{2}=12 y     A)    B)    C)    D)    C)  Graph the equation. - x^{2}=12 y     A)    B)    C)    D)    D)  Graph the equation. - x^{2}=12 y     A)    B)    C)    D)

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Identify the equation without applying a rotation of axes. - x2+8xy+16y22x+4y3=0x ^ { 2 } + 8 x y + 16 y ^ { 2 } - 2 x + 4 y - 3 = 0

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Identify the equation without completing the square. - 3x2+4y2+4x+2y=03 x ^ { 2 } + 4 y ^ { 2 } + 4 x + 2 y = 0

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Find an equation of the parabola described. -Focus at (5, 0); vertex at (0, 0) A) y=20x2y = 20 x ^ { 2 } B) x=20y2x = 20 y ^ { 2 } C) x2=20yx ^ { 2 } = 20 y D) y2=20xy ^ { 2 } = 20 x

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Graph the curve whose parametric equations are given. - x=2t1,y=t2+5;4t4x=2 t-1, y=t^{2}+5 ;-4 \leq t \leq 4  Graph the curve whose parametric equations are given. - x=2 t-1, y=t^{2}+5 ;-4 \leq t \leq 4

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Find the center, transverse axis, vertices, foci, and asymptotes of the hyperbola. - (x4)225(y+1)216=1\frac { ( x - 4 ) ^ { 2 } } { 25 } - \frac { ( y + 1 ) ^ { 2 } } { 16 } = 1

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Find the vertex, focus, and directrix of the parabola with the given equation. - (y+1)2=16(x+3)( y + 1 ) ^ { 2 } = 16 ( x + 3 )

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Find a rectangular equation for the plane curve defined by the parametric equations. -Ron throws a ball straight up with an initial speed of 70 feet per second from a height of 3 feet. Find parametric equations that describe the motion of the ball as a function of time. How long is the ball in the air? When is the Ball at its maximum height? What is the maximum height of the ball? A) x=0x = 0 and y=16t2+40t+6y = - 16 t ^ { 2 } + 40 t + 6 5.284sec,1.25sec5.284 \mathrm { sec } , 1.25 \mathrm { sec } , 25 feet B) x=0x = 0 and y=16t2+40t+6y = - 16 t ^ { 2 } + 40 t + 6 2.34sec,1.25sec2.34 \mathrm { sec } , 1.25 \mathrm { sec } , 5.995.99 feet C) x=0x = 0 and y=16t2+40t+6y = - 16 t ^ { 2 } + 40 t + 6 4.679sec,1.25sec4.679 \mathrm { sec } , 1.25 \mathrm { sec } , 181.21181.21 feet D) x=0x = 0 and y=16t2+40t+6y = - 16 t ^ { 2 } + 40 t + 6 2.642sec,1.25sec2.642 \mathrm { sec } , 1.25 \mathrm { sec } , 31 feet

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Rotate the axes so that the new equation contains no xy-term. Graph the new equation. - 31x2+103xy+21y2144=031 x^{2}+10 \sqrt{3} x y+21 y^{2}-144=0  Rotate the axes so that the new equation contains no xy-term. Graph the new equation. - 31 x^{2}+10 \sqrt{3} x y+21 y^{2}-144=0

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Find an equation for the ellipse described. -Center at (0,0);( 0,0 ) ; focus at (0,2)( 0 , - 2 ) ; vertex at (0,6)( 0,6 )

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Solve the problem. -The orbit of a planet around a sun is an ellipse with the sun at one focus. The aphelion of a planet is its greatest distance from the sun, its perihelion is its shortest distance, and its mean distance is the length of the semimajor Axis of the elliptical orbit. If a planet has a perihelion of 522.2 million miles and a mean distance of 525 million miles, write an equation for the orbit of the planet around the sun. A) x25192+y2516.92=1\frac { x ^ { 2 } } { 519 ^ { 2 } } + \frac { y ^ { 2 } } { 516.9 ^ { 2 } } = 1 B) x25192+y2518.9962=1\frac { x ^ { 2 } } { 519 ^ { 2 } } + \frac { y ^ { 2 } } { 518.996 ^ { 2 } } = 1 C) x2519.0042+y25192=1\frac { x ^ { 2 } } { 519.004 ^ { 2 } } + \frac { y ^ { 2 } } { 519 ^ { 2 } } = 1 D) x25192+y2212=1\frac { x ^ { 2 } } { 519 ^ { 2 } } + \frac { y ^ { 2 } } { 2 \cdot 1 ^ { 2 } } = 1

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Find a rectangular equation for the plane curve defined by the parametric equations. -A baseball player hit a baseball with an initial speed of 160 feet per second at an angle of 40° to the horizontal.The ball was hit at a height of 4 feet off the ground. Find parametric equations that describe the motion of the ball as a function of time. How long is the ball in the air? When is the ball at its maximum height? What is the Distance the ball traveled? A) x=114.9tx = 114.9 t and y=16t2+96.45t+3y = - 16 t ^ { 2 } + 96.45 t + 3 6.059sec,3.014sec6.059 \mathrm { sec } , 3.014 \mathrm { sec } , 1171.7741171.774 feet B) x=114.9tx = 114.9 t and y=16t2+96.45t+3y = - 16 t ^ { 2 } + 96.45 t + 3 5.997sec,3.014sec5.997 \mathrm { sec } , 3.014 \mathrm { sec } , 689.055689.055 feet C) x=122.56tx = 122.56 t and y=16t2+102.88t+4y = - 16 t ^ { 2 } + 102.88 t + 4 6.469sec,3.215sec6.469 \mathrm { sec } , 3.215 \mathrm { sec } , 792.841792.841 feet D) x=122.56tx = 122.56 t and y=16t2+102.88t+4y = - 16 t ^ { 2 } + 102.88 t + 4 12.937sec,3.215sec12.937 \mathrm { sec } , 3.215 \mathrm { sec } , 1,585.5591,585.559 feet

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Match the graph to its equation. -Match the graph to its equation. -

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Solve the problem. -An arch in the form of a semiellipse is 52 ft wide at the base and has a height of 20 ft. How wide is the arch at a height of 12 ft above the base?

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Find an equation of the parabola described. -Focus at (4,0);( 4,0 ) ; vertex at (0,0)( 0,0 )

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Rotate the axes so that the new equation contains no xy-term. Discuss the new equati - 31x2+103xy+21y2144=031 x^{2}+10 \sqrt{3} x y+21 y^{2}-144=0

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Find a rectangular equation for the plane curve defined by the parametric equations. - x=3tant,y=2sect;0t2πx = 3 \tan t , y = 2 \sec t ; 0 \leq t \leq 2 \pi

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Find the center, foci, and vertices of the ellipse. - 2x2+5y212x+60y+188=02 x ^ { 2 } + 5 y ^ { 2 } - 12 x + 60 y + 188 = 0

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Graph the equation. - (y+1)2=8(x1)(y+1)^{2}=8(x-1)  Graph the equation. - (y+1)^{2}=8(x-1)

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Match the equation to the graph. - (x2)2=7(y1)( x - 2 ) ^ { 2 } = 7 ( y - 1 )

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