Exam 5: Applications of the Derivative

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Let f(x)=2x315x236x2f ( x ) = 2 x ^ { 3 } - 15 x ^ { 2 } - 36 x - 2 Then ƒ has a relative minimum at x =

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Let f(x)=x+2+3x1f ( x ) = x + 2 + \frac { 3 } { x - 1 } on [2,7][ 2,7 ] Then the set of all c in (2,7) guaranteed by the Mean Value Theorem is

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The antiderivative of f(x)=11+x2+2xf ( x ) = \frac { 1 } { 1 + x ^ { 2 } } + \frac { 2 } { x } is

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A post office regulation is that the sum of the length and girth of a parcel must not exceed 6 feet. The largest volume in cubic feet of a parcel with square ends is ​

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Let f(x)=sinx+cosxf ( x ) = \sin x + \cos x on [0,2π][ 0,2 \pi ] Then the set of all in c guaranteed by Rolle's Theorem is

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Let f(x)=lnxf ( x ) = \ln x on [1,e][ 1 , e ] Then the set of all c in (1,e) guaranteed by the Mean Value Theorem is

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The particular solution of the differential equation d2ydx2=12x2\frac { d ^ { 2 } y } { d x ^ { 2 } } = 12 x ^ { 2 } satisfying the boundary conditions when x = 0, y = 1 and x = 3, y' = 8 is

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The particular solution of the differential equation d2sdt2=8t3\frac { d ^ { 2 } s } { d t ^ { 2 } } = 8 t - 3 satisfying the initial conditions dsdtx=0=4\left. \frac { d s } { d t } \right| _ { x = 0 } = 4 and s(0)=1s ( 0 ) = 1 is

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The antiderivative of f(x)=3x25x+72xf ( x ) = \frac { 3 x ^ { 2 } - 5 x + 7 } { 2 x } is

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The smallest perimeter possible for a rectangle whose area is 400 square feet is ​

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The largest set on which the function f(x)=3sinxf ( x ) = 3 \sin x on [0,2π][ 0,2 \pi ] is increasing is

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The maximum area of a rectangular piece of land that can be enclosed by 100 yards of fencing is ​

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Determine which of the following is not true for the graph of f(x)=2x2+x1x21f ( x ) = \frac { 2 x ^ { 2 } + x - 1 } { x ^ { 2 } - 1 }

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Let f(x)=x36x29x+1f ( x ) = - x ^ { 3 } - 6 x ^ { 2 } - 9 x + 1 Then ƒ has a relative minimum at x =

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The antiderivative of f(x)=x4+x3f ( x ) = x ^ { 4 } + x - 3 is

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Let f(x)=x39x2+15xf ( x ) = x ^ { 3 } - 9 x ^ { 2 } + 15 x Then ƒ has a relative minimum at x =

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The particular solution of the differential equation d2sdt2=9.8\frac { d ^ { 2 } s } { d t ^ { 2 } } = - 9.8 satisfying the initial conditions [dsdt(0)]=160\left[ \frac { d s } { d t } ( 0 ) \right] = 160 and s(0)=3s ( 0 ) = 3 is

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Let V=43πr3V = \frac { 4 } { 3 } \pi r ^ { 3 } If drdt=2\frac { d r } { d t } = 2 when r=1r = 1 \text {, } then dVdt\frac { d V } { d t } is

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The antiderivative of f(x)=4x+sec2x+1xx21f ( x ) = - 4 ^ { x } + \sec ^ { 2 } x + \frac { 1 } { x \sqrt { x ^ { 2 } - 1 } } is

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The antiderivative of f(x)=(2x3)(x+4)f ( x ) = ( 2 x - 3 ) ( x + 4 ) is

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