Exam 13: Simple Linear Regression Analysis

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A data set with 7 observations yielded the following.Use the simple linear regression model. A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Find the estimated slope. = 21.57 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Find the estimated slope. = 68.31 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Find the estimated slope. = 188.9 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Find the estimated slope. = 5,140.23 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Find the estimated slope. = 590.83 SSE = 1.06 Find the estimated slope.

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A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of monthly tire sales (in thousands of tires)and monthly advertising expenditures (in thousands of dollars).Residuals are calculated for all of the randomly selected six months and ordered from smallest to largest. Determine the normal score for the smallest residual.

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The correlation coefficient is the ratio of explained variation to total variation.

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The slope of the simple linear regression equation represents the average change in the value of the dependent variable per unit change in the independent variable (X).

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Which of the following is a violation of one of the major assumptions of the simple regression model?

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If the points are tightly distributed around the regression line on a scatter diagram,then we can conclude that the changes in the value of the dependent variable _________ the independent variable (X).

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A data set with 7 observations yielded the following.Use the simple linear regression model. A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Determine the 95% confidence interval for the average value of Y when x = 3.25. = 21.57 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Determine the 95% confidence interval for the average value of Y when x = 3.25. = 68.31 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Determine the 95% confidence interval for the average value of Y when x = 3.25. = 188.9 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Determine the 95% confidence interval for the average value of Y when x = 3.25. = 5,140.23 A data set with 7 observations yielded the following.Use the simple linear regression model.   = 21.57   = 68.31   = 188.9   = 5,140.23   = 590.83 SSE = 1.06 Determine the 95% confidence interval for the average value of Y when x = 3.25. = 590.83 SSE = 1.06 Determine the 95% confidence interval for the average value of Y when x = 3.25.

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The following results were obtained from a simple regression analysis: The following results were obtained from a simple regression analysis:   = 37.2895 - (1.2024)X r<sup>2</sup>= .6744 s<sub>b</sub> = .2934 For each unit change in X (independent variable),the estimated change in Y (dependent variable)is equal to: = 37.2895 - (1.2024)X r2= .6744 sb = .2934 For each unit change in X (independent variable),the estimated change in Y (dependent variable)is equal to:

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When using simple linear regression,we would like to use confidence intervals for the _____ and prediction intervals for the _____ at a given value of x.

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An experiment was performed on a certain metal to determine if the strength is a function of heating time.Results based on 10 metal sheets are given below.Use the simple linear regression model. An experiment was performed on a certain metal to determine if the strength is a function of heating time.Results based on 10 metal sheets are given below.Use the simple linear regression model.   = 30   = 104   = 40   = 178   = 134 Determine SSE,SS (Total) = 30 An experiment was performed on a certain metal to determine if the strength is a function of heating time.Results based on 10 metal sheets are given below.Use the simple linear regression model.   = 30   = 104   = 40   = 178   = 134 Determine SSE,SS (Total) = 104 An experiment was performed on a certain metal to determine if the strength is a function of heating time.Results based on 10 metal sheets are given below.Use the simple linear regression model.   = 30   = 104   = 40   = 178   = 134 Determine SSE,SS (Total) = 40 An experiment was performed on a certain metal to determine if the strength is a function of heating time.Results based on 10 metal sheets are given below.Use the simple linear regression model.   = 30   = 104   = 40   = 178   = 134 Determine SSE,SS (Total) = 178 An experiment was performed on a certain metal to determine if the strength is a function of heating time.Results based on 10 metal sheets are given below.Use the simple linear regression model.   = 30   = 104   = 40   = 178   = 134 Determine SSE,SS (Total) = 134 Determine SSE,SS (Total)

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In a simple regression analysis for a given data set,if the null hypothesis β\beta = 0 is rejected,then the null hypothesis ρ\rho = 0 is also rejected.This statement is ___________ true.

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A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.  A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Find the rejection point for the t statistic at  \alpha  = .05 and test H<sub>0</sub>:  \beta <sub>1</sub> = 0 vs.H<sub>a</sub>:  \beta <sub>1</sub>  \neq  0. = 24  A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Find the rejection point for the t statistic at  \alpha  = .05 and test H<sub>0</sub>:  \beta <sub>1</sub> = 0 vs.H<sub>a</sub>:  \beta <sub>1</sub>  \neq  0. = 124  A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Find the rejection point for the t statistic at  \alpha  = .05 and test H<sub>0</sub>:  \beta <sub>1</sub> = 0 vs.H<sub>a</sub>:  \beta <sub>1</sub>  \neq  0. = 42  A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Find the rejection point for the t statistic at  \alpha  = .05 and test H<sub>0</sub>:  \beta <sub>1</sub> = 0 vs.H<sub>a</sub>:  \beta <sub>1</sub>  \neq  0. = 338  A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Find the rejection point for the t statistic at  \alpha  = .05 and test H<sub>0</sub>:  \beta <sub>1</sub> = 0 vs.H<sub>a</sub>:  \beta <sub>1</sub>  \neq  0. = 196 Find the rejection point for the t statistic at α\alpha = .05 and test H0: β\beta 1 = 0 vs.Ha: β\beta 1 \neq 0.

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A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results. A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Calculate the standard error. = 24 A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Calculate the standard error. = 124 A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Calculate the standard error. = 42 A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Calculate the standard error. = 338 A local tire dealer wants to predict the number of tires sold each month.He believes that the number of tires sold is a linear function of the amount of money invested in advertising.He randomly selects 6 months of data consisting of tire sales (in thousands of tires)and advertising expenditures (in thousands of dollars).Based on the data set with 6 observations,the simple linear regression model yielded the following results.   = 24   = 124   = 42   = 338   = 196 Calculate the standard error. = 196 Calculate the standard error.

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Consider the following partial computer output from a simple linear regression analysis. Consider the following partial computer output from a simple linear regression analysis.   Calculate the correlation coefficient. Calculate the correlation coefficient.

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An experiment was performed on a certain metal to determine if the strength is a function of heating time.The simple linear regression equation is An experiment was performed on a certain metal to determine if the strength is a function of heating time.The simple linear regression equation is   = 1 + 1X.The time is in minutes and the strength is measured in pounds per square inch. Provide a managerial interpretation of the slope. = 1 + 1X.The time is in minutes and the strength is measured in pounds per square inch. Provide a managerial interpretation of the slope.

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An experiment was performed on a certain metal to determine if the strength is a function of heating time.The sample size consists of ten metal sheets.Residuals are calculated for all ten metal sheets and ordered from smallest to largest. Determine the normal point for the second largest residual (ninth residual in the ordered array).

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_____ is a statistical technique in which we use observed data to relate a dependent variable to one or more predictor (independent)variables.

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Consider the following partial computer output from a simple linear regression analysis. Consider the following partial computer output from a simple linear regression analysis.   S = 0.4862 R-Sq = ______ Analysis of Variance   Calculate the MSE. S = 0.4862 R-Sq = ______ Analysis of Variance Consider the following partial computer output from a simple linear regression analysis.   S = 0.4862 R-Sq = ______ Analysis of Variance   Calculate the MSE. Calculate the MSE.

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_____ distribution is used for testing the significance of the slope term.

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_____ measures the strength of the linear relationship between the dependent and the independent variable.

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