Exam 4: Exponential and Logarithmic Functions

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For the given functions f and g, find the requested composite function value. - f(x)=x+2,g(x)=3x;f ( x ) = \sqrt { x + 2 } , \quad g ( x ) = 3 x ; \quad Find (fg)(0)( f \circ g ) ( 0 ) .

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Find the domain of the function. - f(x)=ln(1x9)f ( x ) = \ln \left( \frac { 1 } { x - 9 } \right)

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Solve the equation. - 2433x1=272x243 ^ { 3 x - 1 } = 27 ^ { 2 x }

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Find the present value. Round to the nearest cent. -To get $10,000 after 3 years at 6% compounded monthly

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The function f is one-to-one. Find its inverse. - f(x)=2x+8f ( x ) = 2 x + 8

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Find the effective rate of interest. - 614%6 \frac { 1 } { 4 } \% % compounded monthly

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Solve the equation. - 4(1+2x)=1,0244 ( 1 + 2 x ) = 1,024

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Solve the problem. -The logistic growth functi f(t)=4401+6.3e0.2tf ( t ) = \frac { 440 } { 1 + 6.3 e ^ { - 0.2 t } } describes the population of a species of butterflies t months after they are introduced to a non-threatening habitat. What is the limiting size of the butterfly population that the Habitat will sustain?

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Write as the sum and/or difference of logarithms. Express powers as factors. - lney6\ln \sqrt [ 6 ] { \mathrm { ey } }

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Solve the equation. - 32x+3x6=03 ^ { 2 x } + 3 ^ { x } - 6 = 0

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Determine whether the given function is exponential or not. If it is exponential, identify the value of the base a. - () -1 3 0 7 1 11 2 15 3 19

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Solve the problem. -Strontium 90 decays at a constant rate of 2.44% per year. Therefore, the equation for the amount P of strontium 90 after t years is P = P0 e-0.0244t. How long will it take for 15 grams of strontium to decay to 5 grams? Round Answer to 2 decimal places.

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Change the exponential expression to an equivalent expression involving a logarithm. - 73=x7 ^ { 3 } = x

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Solve the problem. -The formul A=180e0.036t\mathrm { A } = 180 \mathrm { e } ^ { 0.036 \mathrm { t } } models the population of a particular city, in thousands, t years after 1998. When will the population of the city reach 287 thousand?

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Find functions f and g so that f fg=Hf \circ g = H - H(x)=43x2H ( x ) = \left| 4 - 3 x ^ { 2 } \right|

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The graph of a one-to-one function f is given. Draw the graph of the inverse function f-1 as a dashed line or curve. - f(x)=x+2f ( x ) = \sqrt { x + 2 }  The graph of a one-to-one function f is given. Draw the graph of the inverse function f-1 as a dashed line or curve. - f ( x ) = \sqrt { x + 2 }     A)    B)     A)  The graph of a one-to-one function f is given. Draw the graph of the inverse function f-1 as a dashed line or curve. - f ( x ) = \sqrt { x + 2 }     A)    B)     B)  The graph of a one-to-one function f is given. Draw the graph of the inverse function f-1 as a dashed line or curve. - f ( x ) = \sqrt { x + 2 }     A)    B)

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Solve the problem. -Conservationists tagged 130 black-nosed rabbits in a national forest in 1990. In 1,991, they tagged 260 black-nosed rabbits in the same range. If the rabbit population follows the exponential law, how many rabbits Will be in the range 9 years from 1990?

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Solve the problem. -In 1992, the population of a country was estimated at 5 million. For any subsequent year, the population, P(t) (in millions), can be modeled using the equation P(t)=2505+44.99e0.0208t\mathrm { P } ( \mathrm { t } ) = \frac { 250 } { 5 + 44.99 \mathrm { e } ^ { - 0.0208 \mathrm { t } } } , where t is the number of years since 1992. Determine the year when the population will be 39 million.

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Solve the problem. -Find a so that the graph of f(x)=logaxf ( x ) = \log _ { a } x contains the point (4,10)( 4,10 ) .

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Find the value of the expression. -Let logbA=2\log _ { \mathrm { b } } \mathrm { A } = 2 and logbB=10\log _ { \mathrm { b } } \mathrm { B } = - 10 . Find logbAB\log _ { \mathrm { b } } \frac { \mathrm { A } } { \mathrm { B } } .

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