Exam 6: Inverse Circular Functions and Trigonometric Equations

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Write the following as an algebraic expression in u, u > 0. - sin(arcsinu3)\sin \left( \arcsin \frac { \mathrm { u } } { \sqrt { 3 } } \right)

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Use the parallelogram rule to find the magnitude of the resultant force for the two forces shown in the figure. Round to one decimal place. -On the given graph of y=secxy = \sec x sketch the graph of y=sec1xy = \sec ^ { - 1 } x as defined in the text. Give the domain and the range.  Use the parallelogram rule to find the magnitude of the resultant force for the two forces shown in the figure. Round to one decimal place. -On the given graph of  y = \sec x  sketch the graph of  y = \sec ^ { - 1 } x  as defined in the text. Give the domain and the range.

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Use a calculator to give the value to the nearest degree. - θ=sin1(0.6561)\theta = \sin ^ { - 1 } ( 0.6561 )

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Solve the equation for exact solutions. - 6cos1x=π6 \cos ^ { - 1 } x = \pi

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Use a calculator to find the value. Give answers as real numbers and round to 4 decimal places, if necessary. -sin (arctan 2)

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Solve the equation (x in radians and in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. - 4tanθ5tan2θ=1\frac { 4 \tan \theta } { 5 - \tan ^ { 2 } \theta } = 1

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Use a calculator to give the real number value. Round the answer to 7 decimal places. - y=sin1(0.6561)y = \sin ^ { - 1 } ( 0.6561 )

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Use a calculator to give the value to the nearest degree. - θ=sin1(0.4848)\theta = \sin ^ { - 1 } ( - 0.4848 )

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Solve the equation for x, where x is restricted to the given interval. - y=8cos3xy = 8 \cos 3 x , for xx in [0,π3]\left[ 0 , \frac { \pi } { 3 } \right]

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Find the exact value of the real number y. - y=tan1(1)y = \tan ^ { - 1 } ( - 1 )

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Give the degree measure of . - θ=arctan(33)\theta = \arctan \left( \frac { \sqrt { 3 } } { 3 } \right)

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Solve the equation for exact solutions. - arctanx=arccot811\arctan x = \operatorname { arccot } \frac { 8 } { 11 }

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Find the exact value of the real number y. - y=sin1(32)y = \sin ^ { - 1 } \left( \frac { \sqrt { 3 } } { 2 } \right)

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Solve the problem. -In an electric circuit, the electromotive force is defined as V=cos2πtV = \cos 2 \pi t , where tt is time in seconds. Solve the equation for t\mathrm { t } .

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Use a calculator to find the value. Give answers as real numbers and round to 4 decimal places, if necessary. - tan(arcsin2)\tan ( \arcsin 2 )

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Graph the inverse circular function. - y=arccsc12xy = \operatorname { arccsc } \frac { 1 } { 2 } x  Graph the inverse circular function. - y = \operatorname { arccsc } \frac { 1 } { 2 } x

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Solve the equation for exact solutions over the interval [0, 2 [0,2π).[ 0,2 \pi ) . - cos2x+2cosx+1=0\cos ^ { 2 } x + 2 \cos x + 1 = 0

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Solve the problem. -In the study of alternating electric current, capacitive voltage is given by VC=i2πfcos2πft\mathrm { V } _ { \mathrm { C } } = - \frac { \mathrm { i } } { 2 \pi \mathrm { f } } \cos 2 \pi \mathrm { ft } \text {, } where f\mathrm { f } is the number of cycles per second, i\mathrm { i } is the maximum current, and t\mathrm { t } is the time in seconds. Solve the equation for tt .

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Graph the inverse circular function. - y=tan1xy=\tan ^{-1} x  Graph the inverse circular function. - y=\tan ^{-1} x

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Find the exact value of the real number y. - y=cos1(32)y = \cos ^ { - 1 } \left( \frac { \sqrt { 3 } } { 2 } \right)

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