Exam 17: Second-Order Differential Equations

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A spring with a 1616 -kg mass has natural length 0.80.8 m and is maintained stretched to a length of 1.21.2 m by a force of 19.619.6 N. If the spring is compressed to a length of 0.40.4 m and then released with zero velocity, find the position x(t)x ( t ) of the mass at any time tt .

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Solve the initial value problem. y+2y3y=0y(0)=7y(0)=1y ^ { \prime \prime } + 2 y ^ { \prime } - 3 y = 0 \quad y ( 0 ) = 7 \quad y ^ { \prime } ( 0 ) = 1

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y=224ex+64e3xy = \frac { 22 } { 4 } e ^ { x } + \frac { 6 } { 4 } e ^ { - 3 x }

The figure shows a pendulum with length L and the angle θ\theta from the vertical to the pendulum. It can be shown that θ\theta , as a function of time, satisfies the nonlinear differential equation d2θdt2+gLsinθ=0\frac { d ^ { 2 } \theta } { d t ^ { 2 } } + \frac { g } { L } \sin \theta = 0 where g=9.8 m/s2g = 9.8 \mathrm {~m} / \mathrm { s } ^ { 2 }  is the acceleration due to gravity. For small values of \text { is the acceleration due to gravity. For small values of } θ\theta we can use the linear approximation sinθ=θ\sin \theta = \theta  and then the differential equation becomes linear. Find the equation \text { and then the differential equation becomes linear. Find the equation }  of motion of a pendulum with length 1 m if θ is initially 0.2rad and the initial \text { of motion of a pendulum with length } 1 \mathrm {~m} \text { if } \theta \text { is initially } 0.2 \mathrm { rad } \text { and the initial }  angular velocity is \text { angular velocity is } dθdt=1rad/s\frac { d \theta } { d t } = 1 \mathrm { rad } / \mathrm { s }  The figure shows a pendulum with length L and the angle  \theta  from the vertical to the pendulum. It can be shown that  \theta  , as a function of time, satisfies the nonlinear differential equation  \frac { d ^ { 2 } \theta } { d t ^ { 2 } } + \frac { g } { L } \sin \theta = 0  where  g = 9.8 \mathrm {~m} / \mathrm { s } ^ { 2 }   \text { is the acceleration due to gravity. For small values of }   \theta  we can use the linear approximation  \sin \theta = \theta   \text { and then the differential equation becomes linear. Find the equation }   \text { of motion of a pendulum with length } 1 \mathrm {~m} \text { if } \theta \text { is initially } 0.2 \mathrm { rad } \text { and the initial }   \text { angular velocity is }   \frac { d \theta } { d t } = 1 \mathrm { rad } / \mathrm { s }

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A series circuit consists of a resistor R=32ΩR = 32 \Omega , an inductor with L=4HL = 4 H , a capacitor with C=0.003125 FC = 0.003125 \mathrm {~F} , and a 2424 -V battery. If the initial charge is 0.0008 C and the initial current is 0, find the current I(t) at time t.

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Solve the differential equation. y8y+25y=0y ^ { \prime \prime } - 8 y ^ { \prime } + 25 y = 0

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Suppose a spring has mass M and spring constant k and let ω=k/M\omega = \sqrt { k / M } . Suppose that the damping constant is so small that the damping force is negligible. If an external force F(t)=8F0cos(ωt)F ( t ) = 8 F _ { 0 } \cos ( \omega t ) is applied (the applied frequency equals the natural frequency), use the method of undetermined coefficients to find the equation that describes the motion of the mass.

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A spring with a mass of 2 kg has damping constant 14, and a force of 3.63.6 N is required to keep the spring stretched 0.30.3 m beyond its natural length. The spring is stretched 1m beyond its natural length and then released with zero velocity. Find the position x(t) of the mass at any time t.

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A spring with a 3-kg mass is held stretched 0.9 m beyond its natural length by a force of 30 N. If the spring begins at its equilibrium position but a push gives it an initial velocity of 11 m/s, find the position x(t) of the mass after t seconds.

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Solve the initial-value problem. y+49y=0,y(π7)=0,y(π7)=1y ^ { \prime \prime } + 49 y = 0 , y \left( \frac { \pi } { 7 } \right) = 0 , y ^ { \prime } \left( \frac { \pi } { 7 } \right) = 1

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A series circuit consists of a resistor R=20ΩR = 20 \Omega an inductor with L = 11 H, a capacitor with C = 0.002000.00200 F, and a 1212 -V battery. If the initial charge and current are both 0, find the charge Q(t) at time t.

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Solve the differential equation using the method of variation of parameters. y4y+3y=2sinxy ^ { \prime \prime } - 4 y ^ { \prime } + 3 y = 2 \sin x

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Solve the differential equation using the method of variation of parameters. y5y+4y=sinxy ^ { \prime \prime } - 5 y ^ { \prime } + 4 y = \sin x

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Solve the initial-value problem. 2y+21y+54y=0,y(0)=0,y(0)=52 y ^ { \prime \prime } + 21 y ^ { \prime } + 54 y = 0 , y ( 0 ) = 0 , y ^ { \prime } ( 0 ) = 5

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Solve the initial-value problem. y+81y=0,y(π9)=0,y(π9)=8y ^ { \prime \prime } + 81 y = 0 , y \left( \frac { \pi } { 9 } \right) = 0 , y ^ { \prime } \left( \frac { \pi } { 9 } \right) = 8

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Solve the differential equation using the method of variation of parameters. y+4y+4y=e2xx3y ^ { \prime \prime } + 4 y ^ { \prime } + 4 y = \frac { e ^ { - 2 x } } { x ^ { 3 } }

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A series circuit consists of a resistor R=96ΩR = 96 \Omega , an inductor with L=8HL = 8 \mathrm { H } , a capacitor with C=0.00125 FC = 0.00125 \mathrm {~F} , and a generator producing a voltage of E(t)=48cos(10t)E ( t ) = 48 \cos ( 10 t ) If the initial charge is Q=0.001CQ = 0.001 \mathrm { C } and the initial current is 0, find the charge Q(t)Q ( t ) at time t.

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Solve the initial-value problem. y+2y3y=0,y(0)=2,y(0)=1y ^ { \prime \prime } + 2 y ^ { \prime } - 3 y = 0 , y ( 0 ) = 2 , y ^ { \prime } ( 0 ) = 1

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Solve the differential equation. 49y+y=049 y ^ { \prime \prime } + y = 0

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Solve the differential equation using the method of undetermined coefficients. y+9y=7e2xy ^ { \prime \prime } + 9 y = 7 e ^ { 2 x }

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Solve the initial-value problem. y2y24y=0,y(1)=4,y(1)=5y ^ { \prime \prime } - 2 y ^ { \prime } - 24 y = 0 , y ( 1 ) = 4 , y ^ { \prime } ( 1 ) = 5 .

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