Exam 2: Matrix Algebra

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Find a basis for the column space of the matrix. - B=[10503014040001100000]B = \left[ \begin{array} { r r r r r } 1 & 0 & - 5 & 0 & - 3 \\0 & 1 & 4 & 0 & 4 \\0 & 0 & 0 & 1 & 1 \\0 & 0 & 0 & 0 & 0\end{array} \right]

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Find an LU factorization of the matrix A. - A=[41249]A = \left[ \begin{array} { r r } 4 & - 1 \\- 24 & 9\end{array} \right]

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