Exam 3: Graphs and Functions
Exam 1: Review of Basic Concepts637 Questions
Exam 2: Equations and Inequalities498 Questions
Exam 3: Graphs and Functions531 Questions
Exam 4: Polynomials and Rational Functions517 Questions
Exam 5: Inverse, Exponential, and Logarithmic Functions472 Questions
Exam 6: Systems and Matrices505 Questions
Exam 7: Arithmetic Sequence: Common Difference and First n Terms570 Questions
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Write an equation for the line described. Write the equation in the form specified.
-parallel to , through ; slope-intercept form
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The graph of y = f(x) is given. Use the graph to find the function value.
-Find f(3). 

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Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint.
-midpoint , endpoint
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Find the center-radius form of the circle described or graphed.
-

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Find the center-radius form of the equation of the circle.
-center (10, 0), radius 3
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Give a rule for the piecewise-defined function. Then give the domain and range.
-

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Consider the function h as defined. Find functions f and g so tha
-
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Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint.
-midpoint , endpoint
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A new chocolate company is estimating how many candy bars per week college students will consume of their line of
products. The graph shows the probable number of candy bars students (age 18-22) will consume from year 0 to year 10.
B(x) gives the number of candy bars for boys, G(x) gives the number of candy bars for girls, and T(x) gives the total
number for both groups. Use the graph to answer the question.
-Use the slopes of the line segments to decide in which period ( or the number of candy bars per week increased more rapidly.

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Graph the point symmetric to the given point.
-Plot the point (4, 1), then plot the point that is symmetric to (4, 1) with respect to the origin.

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Describe the transformations and give the equation for the graph.
-

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Graph the point symmetric to the given point.
-Plot the point (5, 0), then plot the point that is symmetric to (5, 0) with respect to the origin.

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