Exam 4: Molecular Information Flow and Protein Processing

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GTP provides energy for

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The template for RNA polymerase is ________, and the new RNA molecule is ________ to the template.

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AT-rich DNA will denature/melt

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DNA participates in protein synthesis through

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DNA replication is started with a(n) ________, which, in most cases, in vivo is a short stretch of ________.

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The flow of biological information begins with

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Termination of RNA synthesis is ultimately determined by

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RNA is incapable of forming secondary structure.

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The function of the DNA polymerase is to catalyze

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You experimentally change the DNA sequence directly upstream of a start codon of an operon in E. coli to investigate the function of this region of DNA. Analysis reveals that after the change the same amount of mRNA is made from the operon, but there are very few proteins made from the operon. What is the most likely function of the DNA sequence that you changed?

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Speculate why the half-life of mRNA is short, while the half-lives of rRNA and tRNA are long.

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An operon is a useful genetic element, because it

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Supercoiling is important for DNA structure, because

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Which of the following statements is TRUE concerning mRNA?

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Throughout the living world, the genetic code is generally universal; however, there are slight variations.

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Which of the following is NOT correct regarding DNA and RNA synthesis?

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How are plasmids different than chromosomes?

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You are trying to design a protein that will be expressed in Escherichia coli and secreted outside of the cell for purification and use as a pharmaceutical. E. coli is a gram-negative cell and the protein folds after it has exited the cell. Which secretion system would work best for this project? Support your answer with evidence based on the properties of E. coli, the protein, and the secretion system.

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Explain how Escherichia coli can grow with a doubling time of 20 minutes when chromosome replication takes 40 minutes.

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Aminoacyl-tRNA synthetase catalyzes the reaction between the appropriate amino acid and ATP to form an activated amino acid: amino acid + ATP ↔ aminoacyl-AMP + P-P.

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