Exam 5: Modeling With Higher-Order Differential Equations

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The eigenvalue problem y+λy=0,y(0)=0,y(π/2)=0y ^ { \prime \prime } + \lambda y = 0 , y ( 0 ) = 0 , y ( \pi / 2 ) = 0 has the solution

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The solution of the differential equation of the previous problem is

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In the previous problem, the solution for the velocity, vv , is

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A spring attached to the ceiling is stretched 2.45 meters by a four kilogram mass. The value of the Hooke's Law spring constant, kk , is

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In the previous problem, if the mass is set in motion, the natural frequency, ω\omega ,is

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The initial value problem (Lx)d2xdt2(dxdt)2=Lg,x(0)=0,x(0)=0( L - x ) \frac { d ^ { 2 } x } { d t ^ { 2 } } - \left( \frac { d x } { d t } \right) ^ { 2 } = L g , x ( 0 ) = 0 , x ^ { \prime } ( 0 ) = 0 is a model of a chain of length LL falling to the ground, where x(t)x ( t ) represents the length of chain on the ground at time tt . The solution for v=dxdtv = \frac { d x } { d t } in terms of xx is

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A pendulum of length 16 feet hangs from the ceiling. Let g=32g = 32 represent the gravitational acceleration. The correct linearized differential equation for the angle, θ\theta , that the swinging pendulum makes with the vertical is

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The boundary value problem Td2ydx2+ρω2=0,y(0)=0,y(L)=0T \frac { d ^ { 2 } y } { d x ^ { 2 } } + \rho \omega ^ { 2 } = 0 , y ( 0 ) = 0 , y ( L ) = 0 is a model of the shape of a rotating string. Suppose TT and ρ\rho are constants. The critical angular rotation speed ω=ωn\omega = \omega _ { n } , for which there exist non-trivial solutions are

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In the previous problem, if y(0)=Ry ( 0 ) = R , the escape velocity is

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The solution of the boundary value problem in the previous problem is

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The solution of a vibrating spring problem is x=4cost3sintx = 4 \cos t - 3 \sin t . The amplitude is

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A 10 foot chain of weight density 2 pounds per foot is coiled on the ground. One end is pulled upward by a force of 10 pounds. The correct differential equation for the height, x(t)x ( t ) , of the end of the chain above the ground at time tt is

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A beam of length LL is simply supported at the left end embedded at right end. The weight density is constant, ω(x)=ω0\omega ( x ) = \omega _ { 0 } . Let y(x)y ( x ) represent the deflection at point xx . The correct form of the boundary value problem for this beam is

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The eigenvalue problem y+λy=0,y(0)=0,y(π/2)=0y ^ { \prime \prime } + \lambda y = 0 , y ^ { \prime } ( 0 ) = 0 , y ^ { \prime } ( \pi / 2 ) = 0 has the solution

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In the previous problem, the solution for the velocity, vv , is

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A rocket with mass mm is launched vertically upward from the surface of the earth with a velocity v0v _ { 0 } . Let y(t)y ( t ) be the distance of the rocket from the center of the earth at time tt . Assuming that the only force acting on the rocket is gravity, which is inversely proportional to the square of the distance from the center of the earth, the correct differential equation for the position of the rocket is

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In the previous two problems, if the mass is set into motion in a medium that imparts a damping force numerically equal to 16 times the velocity, the correct differential equation for the position, x(t)x ( t ) , of the mass at a function of time, tt , is

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In the previous problem the corresponding non-trivial solutions for yy are

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The boundary value problem rd2udr2+2dudr=0,u(a)=u0,u(b)=u1r \frac { d ^ { 2 } u } { d r ^ { 2 } } + 2 \frac { d u } { d r } = 0 , u ( a ) = u _ { 0 } , u ( b ) = u _ { 1 } is a model for the temperature distribution between two concentric spheres of radii aa and bb , with a<ba < b .The solution of this problem is

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The eigenvalue problem y+λy=0,y(0)=0,y(1)=0y ^ { \prime \prime } + \lambda y = 0 , y ( 0 ) = 0 , y ( 1 ) = 0 has the solution

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