Exam 8: Basic Concepts of Chemical Bonding

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Which of the following would have to lose two electrons in order to achieve a noble gas electron configuration ? Which of the following would have to lose two electrons in order to achieve a noble gas electron configuration ?

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In the Lewis symbol for a fluorine atom, there are paired and unpaired electrons.

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The Lewis structure of the CO32- ion is .

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A valid Lewis structure of _ _ cannot be drawn without violating the octet rule.

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Of the molecules below, the bond in is the most polar.

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Of the following, cannot accommodate more than an octet of electrons.

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Using the table of bond dissociation energies, the OH for the following gas- phase reaction is KJ) Using the table of bond dissociation energies, the OH for the following gas- phase reaction is KJ)    Using the table of bond dissociation energies, the OH for the following gas- phase reaction is KJ)

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Of the possible bonds between carbon atoms (single, double, and triple), _.

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Of the atoms below, is the most electronegative.

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As the number of covalent bonds between two atoms increases, the distance between the atoms And the strength of the bond between them _ _.

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Of the bonds below, is the least polar.

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As electronegativity difference increases, bond length will decrease.

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The electron configuration that corresponds to the Lewis symbol, :

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The formal charge on sulfur in SO42- is , where the Lewis structure of the ion is: The formal charge on sulfur in SO<sub>4</sub><sup>2</sup><sup>-</sup><sup> </sup>is , where the Lewis structure of the ion is:

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The type of compound that is most likely to contain a covalent bond is _.

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Which of the following would have to gain two electrons in order to achieve a noble gas electron configuration _ ? O Sr Na Se Br

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Of the bonds C- N, C=N, and C÷N, the C- N bond is .

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Using the table of average bond energies below, the OH for the reaction is kJ. Using the table of average bond energies below, the OH for the reaction is kJ.    Using the table of average bond energies below, the OH for the reaction is kJ.

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The bond length in an HI molecule is 1.61 Å and the measured dipole moment is 0.44 D. What is the magnitude (in units of e) of the negative charge on I in HI? (1 debye = 3.34 × 10- 34 coulomb- meters; ; e=1.6 × 10- 19 coulombs)

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For resonance forms of a molecule or ion, .

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