Exam 3: Introduction to Logic

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Construct a truth table for the statement. - s(ps)\sim \mathrm{s} \vee(\sim \mathrm{p} \vee \mathrm{s})

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Label the pair of statements as either contrary or consistent. -That old book is full of recipes. That book is very expensive.

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Decide whether the statement is compound. - 4\sqrt { 4 } is rational and 6\sqrt { 6 } is irrational.

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Decide whether the statement is compound. -If it rains, we won't play soccer.

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Use a truth table to determine whether the argument is valid. - pq p \vee q (pq)q \frac{\sim(p \vee q)}{\sim q}

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 Write the negation of the conditional. Use the fact that the negation of pq is pq\text { Write the negation of the conditional. Use the fact that the negation of } p \rightarrow q \text { is } p \wedge \sim q \text {. } -If she doesn't study, she won't pass her math test.

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Rewrite the statement using the if...then connective. Rearrange the wording or words as necessary. -All chocolate is good.

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Decide whether the statement is true or false. -All whole numbers are real numbers.

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Tell whether the conditional statement is true or false. - (5225)(2+3=5)( 52 \neq 25 ) \rightarrow ( 2 + 3 = 5 )

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Use an Euler diagram to determine whether the argument is valid or invalid. -Some cars are considered sporty.  Some cars are safe at high speeds. \underline { \text { Some cars are safe at high speeds. } } Some sports cars are safe at high speeds.

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Write a logical statement representing the following circuit. Simplify when possible. - [(pr)q](qr)[ ( p \wedge \sim r ) \vee q ] \wedge ( q \wedge \sim r )

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The argument has a true conclusion. Identify the argument as valid or invalid. - 14\sqrt { 14 } is less than 14 . 7 is less than 14\underline { \text {7 is less than }\sqrt { 14 } } 14\sqrt { 14 } is less than 7.7 .

(Multiple Choice)
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Write the compound statement in symbols. Let r=r = "The food is good." p= "I eat too much." q= "I'll exercise." -If I exercise, then the food won't be good and I won't eat too much.

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Label the pair of statements as either contrary or consistent. -Today is Tuesday. Today it is raining.

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Solve the problem. -Given that (pq)p( p \vee q ) \vee \sim p is true, what can you conclude about the truth values of pp and qq ?

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 Write the negation of the conditional. Use the fact that the negation of pq is pq\text { Write the negation of the conditional. Use the fact that the negation of } p \rightarrow q \text { is } p \wedge \sim q \text {. } -If you give your hat to the doorman, he will give you a dirty look.

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Construct a truth table for the statement. - (pq)(qp)( \sim \mathrm { p } \vee \sim \mathrm { q } ) \rightarrow \sim ( \mathrm { q } \wedge \mathrm { p } )

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Tell whether the conditional statement is true or false. -Here T represents a true statement. T(3>5)\mathrm { T } \rightarrow ( - 3 > - 5 )

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Write the converse, inverse, or contrapositive of the statement as requested. -All Border Collies are dogs. Inverse

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Rewrite the statement in the form "if p, then q". -I won't go until it's 11 pm.

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