Exam 5: Integrals

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Find the partial fraction expansion of the rational function: 9(x+1)2(2x)\frac { 9 } { ( x + 1 ) ^ { 2 } ( 2 - x ) } .

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Let f (x) = 2x+12 x + 1 on the interval [ - 1,1]. Let the interval be divided into four equal subintervals. Find the value of the Riemann sum i=14f(xi)Δxi if xi\sum _ { i = 1 } ^ { 4 } f \left( x _ { i } ^ { * } \right) \Delta x _ { i } \text { if } x _ { i } ^ { * } is the left endpoint of its subinterval.

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Given the graph below, use 5 rectangles to estimate the area under the graph from x = 0 to x = 5. Compute L5 (sample points are left endpoints), R5 (sample points are right endpoints) and M5 (sample points are midpoints). Which of the estimates appears to give the best estimate? Justify your answer. Given the graph below, use 5 rectangles to estimate the area under the graph from x = 0 to x = 5. Compute L<sub>5</sub> (sample points are left endpoints), R<sub>5 </sub>(sample points are right endpoints) and M<sub>5</sub> (sample points are midpoints). Which of the estimates appears to give the best estimate? Justify your answer.

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L5 \approx 44.8; R5 \approx 28.8; M5 \approx 36.2; Since the graph of the function is decreasing, using midpoints appears to give the best approximation.

Let f(x)={0 if x<02x if 0x1 and g(x)=0xf(t)dt.2 if 1<xf ( x ) = \left\{ \begin{array} { l l l } 0 & \text { if } & x < 0 \\2 x & \text { if } & 0 \leq x \leq 1 \text { and } g ( x ) = \int _ { 0 } ^ { x } f ( t ) d t . \\2 & \text { if } & 1 < x\end{array} \right. (a) Find an expression for g (x) similar to the one for f (x).(b) Where is f differentiable? Where is g differentiable?

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Evaluate 11(21x2)dx\int _ { - 1 } ^ { 1 } \left( 2 - \sqrt { 1 - x ^ { 2 } } \right) d x by interpreting the integral in terms of area.

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Find the value of the integral 33x1+3x2dx\int _ { - 3 } ^ { 3 } \frac { x } { \sqrt { 1 + 3 x ^ { 2 } } } d x

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What is the value of the estimate using four approximating rectangles and taking sample points to be right-hand endpoints?

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Given the graph of y=h(x)y = h ( x ) below:  Given the graph of  y = h ( x )  below:   (a) Find c in [0,6] which will maximize  \int _ { 0 } ^ { c } h ( x ) d x  (b) Show that  \int _ { - 1 } ^ { 3 } h ( x ) d x  is between 4 and 7. (a) Find c in [0,6] which will maximize 0ch(x)dx\int _ { 0 } ^ { c } h ( x ) d x (b) Show that 13h(x)dx\int _ { - 1 } ^ { 3 } h ( x ) d x is between 4 and 7.

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Prove that x33cosx\frac { - x ^ { 3 } } { 3 } \cos x is not an antiderivative of x2sinxx ^ { 2 } \sin x .

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Evaluate the improper integral 0e3xdx\int _ { 0 } ^ { \infty } e ^ { - 3 x } d x

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A particle travels along a line. Its velocity in meters per second is given by v(t)=3t212tv ( t ) = 3 t ^ { 2 } - 12 t Find (a) the displacement from t = 0 to t = 8.(b) the distance traveled by the particle from t = 0 to t = 8.

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Suppose we wish to estimate the area under the curve y = x between x = 1 and x = 2 using 2 subintervals of equal length. What is the largest value the approximation could have?

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Intelligence Quotient (IQ) scores are assumed to be normally distributed in the population. The probability that a person selected at random from the general population will have an IQ between 100 and 120 is given by 02p(x)dx\int _ { 0 } ^ { 2 } p ( x ) d x Use the graph of p (x) graphed below to answer the questions which follow:  Intelligence Quotient (IQ) scores are assumed to be normally distributed in the population. The probability that a person selected at random from the general population will have an IQ between 100 and 120 is given by  \int _ { 0 } ^ { 2 } p ( x ) d x  Use the graph of p (x) graphed below to answer the questions which follow:    (a) Use Simpson's Rule with n = 4 to approximate  \int _ { 0 } ^ { 2 } p ( x ) d x   (b) The probability that a person selected from the general population will have an IQ score between 80 and 120 is given by  \int _ { - 2 } ^ { 2 } p ( x ) d x  What is the approximate value of  \int _ { - 2 } ^ { 2 } p ( x ) d x ?  (c) Since p (x) represents a probability distribution, the entire area of the region under the graph is exactly 1. Using this information, what is the approximate probability that a person selected at random from the general population will have an IQ score over 120? (a) Use Simpson's Rule with n = 4 to approximate 02p(x)dx\int _ { 0 } ^ { 2 } p ( x ) d x (b) The probability that a person selected from the general population will have an IQ score between 80 and 120 is given by 22p(x)dx\int _ { - 2 } ^ { 2 } p ( x ) d x What is the approximate value of 22p(x)dx?\int _ { - 2 } ^ { 2 } p ( x ) d x ? (c) Since p (x) represents a probability distribution, the entire area of the region under the graph is exactly 1. Using this information, what is the approximate probability that a person selected at random from the general population will have an IQ score over 120?

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Use the Midpoint Rule with 2 equal subdivisions to get an approximation for ln 5.

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Use (a) the Trapezoidal Rule with n = 8 and (b) Simpson's Rule with n = 8 to approximate 02exdx\int _ { 0 } ^ { 2 } e ^ { x } d x Round your answers to six decimal places.

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Given functions of ff and gg , use the facts that 04f(x)dx=4\int _ { 0 } ^ { 4 } f ( x ) d x = 4 , 46f(x)dx=3\int _ { 4 } ^ { 6 } f ( x ) d x = 3 06g(x)dx=5, and 26g(x)dx=4\int _ { 0 } ^ { 6 } g ( x ) d x = - 5 \text {, and } \int _ { 2 } ^ { 6 } g ( x ) d x = - 4 to evaluate the following integrals: (a) 04(3f(x)+1)dx\int _ { 0 } ^ { 4 } ( 3 \cdot f ( x ) + 1 ) d x (b) 06f(x)dx\int _ { 0 } ^ { 6 } f ( x ) d x (c) 06[f(x)4g(x)]dx\int _ { 0 } ^ { 6 } [ f ( x ) - 4 \cdot g ( x ) ] d x (d) 02g(x)dx\int _ { 0 } ^ { 2 } g ( x ) d x

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Let f(x)=x234t33dt. Find f(x)f ( x ) = \int _ { x ^ { 2 } } ^ { 3 } \sqrt [ 3 ] { 4 - t ^ { 3 } } d t . \text { Find } f ^ { \prime } ( x )

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What is the largest value of 03f(x)dx\int _ { 0 } ^ { 3 } | f ( x ) | d x if 4f(x)2- 4 \leq f ( x ) \leq 2 .

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Sketch a plane region whose area is equal to limn{i=1n[4(2in)2]2n}\lim _ { n \rightarrow \infty } \left\{ \sum _ { i = 1 } ^ { n } \left[ \sqrt { 4 - \left( \frac { 2 i } { n } \right) ^ { 2 } } \right] \frac { 2 } { n } \right\} then fine the limit.

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Evaluate 3x+2x1dx\int \frac { 3 x + 2 } { x - 1 } d x

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