Exam 7: Differential Equations

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Newton's Law of Cooling states that the rate at which a body changes temperature is proportional to the difference between its temperature and the temperature of the surrounding medium. Suppose that a body has an initial temperature of 250 ^\circ F and that after one hour the temperature is 200 ^\circ F. Assuming that the surrounding air is kept at a constant temperature of 72 ^\circ F, determine the temperature of the body at time tt .

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dTdt=k(T72),T(0)=250F,T(1)=200FT(t)=72+178(128178)t\frac { d T } { d t } = k ( T - 72 ) , T ( 0 ) = 250 ^ { \circ } \mathrm { F } , T ( 1 ) = 200 ^ { \circ } \mathrm { F } \Rightarrow T ( t ) = 72 + 178 \left( \frac { 128 } { 178 } \right) ^ { t }

A direction field for a differential equation is given below:  A direction field for a differential equation is given below:    (a) Sketch the graphs of the solutions that have initial condition  P  and initial condition  Q  . (b) Determine whether the differential equation is autonomous. Explain your answer. (a) Sketch the graphs of the solutions that have initial condition PP and initial condition QQ . (b) Determine whether the differential equation is autonomous. Explain your answer.

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(a)  (a)    (b) It is not autonomous since  \frac { d y } { d x }  is dependent on both  x  and  y  .
(b) It is not autonomous since dydx\frac { d y } { d x } is dependent on both xx and yy .

The study of free fall provides one context to consider differential equations. In the simplest case, in the absence of air or other resistance, physicists assume that the rate of change of velocity of a body is constant.(a) Write an equation for dvdt\frac { d v } { d t } .(b) As the time tt increases without bound, what happens to the velocity V\mathcal { V } ?

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(a) dvdt=a\frac { d v } { d t } = a where aa is a constant.
(b) Since v(t)=at+v0v ( t ) = a t + v _ { 0 } , where vov _ { o } is a constant, therefore as tt increases without bound, v(t)v ( t ) will increase without bound.

Suppose dydx=y2x\frac { d y } { d x } = \frac { y ^ { 2 } } { x } , y(1)=2y ( 1 ) = 2 . Use Euler's method with step size h=1h = 1 to approximate y(3)y ( 3 ) .

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Find the solution of the initial-value problem dydt=2t1y\frac { d y } { d t } = 2 t \sqrt { 1 - y } , y(1)=0y ( 1 ) = 0 .

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Solve the initial-value problem tdydt=y(y1)t \frac { d y } { d t } = y ( y - 1 ) , y(2)=4y ( 2 ) = 4 .

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Solve the initial-value problem dydt=2ty2+3y2\frac { d y } { d t } = 2 t y ^ { 2 } + 3 y ^ { 2 } , y(0)=1y ( 0 ) = 1 . Then use your solution to evaluate y(1)y ( 1 ) .

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The brakes of a car traveling 60mph60 \mathrm { mph } decelerate the car at the rate of 20 ft/s2.(a) Determine the differential equation that the position function y(t)y ( t ) satisfies.(b) What are the initial conditions? (c) If the car is 175 feet 175 \text { feet } from a barrier when the brakes are applied, will it hit the barrier?

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Consider the differential equation xdydx3y=0x \frac { d y } { d x } - 3 y = 0 .(a) Sketch the direction field. Indicate where the slopes are 1- 1 , 0, or 1. Draw some other slopes as well.(b) If the point (1,2)( 1,2 ) is on the graph of a solution, use Euler's Method with step size 0.50.5 to estimate the value of the solution at x=2x = 2 .

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Suppose a population growth is modeled by the logistic equation dPdt=0.01P0.0001P2\frac { d P } { d t } = 0.01 P - 0.0001 P ^ { 2 } with P(0) = 10. Find the formula for the population after t years.

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Find the orthogonal trajectories of the family of curves y=kx2y = k x ^ { 2 } . Then draw several members of each family on the same coordinate plane.

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A direction field is given below. Which of the following represents its differential equation? A direction field is given below. Which of the following represents its differential equation?

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A predator-prey system is modeled by the system of differential equations dxdt=axbxy\frac { d x } { d t } = a x - b x y , dydt=cy+dxy\frac { d y } { d t } = - c y + d x y , where a, b, c, and d are positive constants.(a) Which variable, x or y, represents the predator? Defend your choice.(b) Show that the given system of differential equations has the two equilibrium solutions {x+0,y=0}\{ x + 0 , y = 0 \} and {x=cd,y=ab}\left\{ x = \frac { c } { d } , y = \frac { a } { b } \right\} .(c) Explain the significance of each of the equilibrium solutions.

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The radioactive isotope Bismuth-210 has a half-life of 5 days. Suppose we have an initial amount of 100 mg. The amount of Bismuth-210 remaining after tt days is

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Solve the initial-value problem dydt=2ty2+t2y2\frac { d y } { d t } = \frac { 2 t } { y ^ { 2 } + t ^ { 2 } y ^ { 2 } } , y(0)=3y ( 0 ) = 3 . Then use your solution to evaluate y(e1)y ( \sqrt { e - 1 } ) .

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Consider the differential equation dydt=yt\frac { d y } { d t } = y - t .(a) What are the equilibrium solutions? (b) What are the points in the tyt y -plane at which the slope of the solution curve is 00 ? (c) What are the points in the tyt y -plane at which the slope of the solution curve is 11 ? (d) What are the points in the tyt y -plane at which the slope of the solution curve is -1? (e) Use the information from above to sketch the direction field for the given differential equation.

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(a) Determine the solution of the differential equation dydx=y\frac { d y } { d x } = - y where y(0)=1y ( 0 ) = 1 .(b) Use the solution y(x)y ( x ) from part (a) to calculate y(0.4)y ( 0.4 ) .(c) Use Euler's Method with the given step sizes to estimate the value of y(0.4)y ( 0.4 ) for the equation given in part (a).(i) h=0.4h = 0.4 (ii) h=0.2h = 0.2 (iii) h=0.1h = 0.1 (d) Sketch y(x)y ( x ) from part (b) and each of the Euler approximations from part (c) on the same set of axes.

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The growth of a population is modeled by the differential equation dPdt=0.2P101\frac { d P } { d t } = 0.2 P ^ { 101 } , and the initial population is P(0)=2P ( 0 ) = 2 Find P(50)P ( 50 )

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When a child was born, her grandparents deposited $1000 in a saving account at 5% interest compounded continuously. The amount of money after t years is:

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Suppose that we model populations of predators and preys (in millions) with the system of differential equations: =2x-1.2xy =-y+0.9xy Find the equilibrium solution.

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