Exam 16: The Structural Basis of Cellular Information: Dna, chromosomes, and the Nucleus
Exam 1: A Preview of Cell Biology56 Questions
Exam 2: The Chemistry of the Cell57 Questions
Exam 3: The Macromolecules of the Cell58 Questions
Exam 4: Cells and Organelles58 Questions
Exam 5: Bioenergetics: the Flow of Energy in the Cell44 Questions
Exam 6: Enzymes: the Catalysts of Life52 Questions
Exam 7: Membranes: Their Structure,function,and Chemistry61 Questions
Exam 8: Transport Across Membranes: Overcoming the Permeability Barrier58 Questions
Exam 9: Chemotrophic Energy Metabolism: Glycolysis and Fermentation60 Questions
Exam 10: Chemotrophic Energy Metabolism: Aerobic Respiration58 Questions
Exam 11: Phototrophic Energy Metabolism: Photosynthesis58 Questions
Exam 12: The Endomembrane System54 Questions
Exam 13: Cytoskeletal Systems61 Questions
Exam 14: Cellular Movement: Motility and Contractility62 Questions
Exam 15: Beyond the Cell: Cell Adhesions, cell Junctions, and Extracellular Structures60 Questions
Exam 16: The Structural Basis of Cellular Information: Dna, chromosomes, and the Nucleus56 Questions
Exam 17: DNA Replication, repair, and Recombination53 Questions
Exam 18: Gene Expression: Ithe Genetic Code and Transcription54 Questions
Exam 19: Gene Expression: Iiprotein Synthesis and Sorting57 Questions
Exam 20: The Regulation of Gene Expression56 Questions
Exam 21: Molecular Biology Techniques for Cell Biology56 Questions
Exam 22: Signal Transduction Mechanisms: Ielectrical and Synaptic Signaling in Neurons53 Questions
Exam 23: Signal Transduction Mechanisms: Iimessengers and Receptors65 Questions
Exam 24: The Cell Cycle and Mitosis66 Questions
Exam 25: Sexual Reproduction,meiosis,and Genetic Recombination64 Questions
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Each of the following structures is found within the nucleus of a eukaryotic cell except
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Avery,MacLeod,and McCarty (1944)demonstrated that DNA was the genetic material by treating heat-killed Streptococcus pneumoniae S (smooth)strain with DNase,thereby preventing transfer of the "transforming substance" from the killed S strain to the live R (rough)strain when the two were mixed together and injected into mice.Another way that one could demonstrate transformation in bacteria would be to extract DNA from
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In an experiment like that of the 1952 Hershey and Chase experiments,35S was added to a phage replicating within its bacterial host.The new phage particles were carefully isolated and used to infect fresh bacterial cells in the absence of any radioisotopes.Where would you expect to find the 35S radioisotope immediately after infection?
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Heterochromatin is highly ________,thus constitutive heterochromatin plays a(n)________ role and facultative heterochromatin functions in ________.
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The base composition in DNA isolated from cow liver cells is 28% adenine; what percent of the bases are cytosine?
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Fluorescent in situ hybridization (FISH)would be helpful in determining
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Alteration of histones by addition of methyl and acetyl groups to particular amino acids
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Mitochondrial DNA can be used to identify a species based upon
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Which of the following are components of Chargaff's rules of bases?
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________ is the process of synthesizing proteins based on the base sequences in mRNA molecules.
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The information encoded in DNA is used within a cell in a two-stage process.The two stages of this process are called
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________ are amino acid sequences that are recognized by importin,allowing proteins to enter the nucleus.
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The proteins that compose the nuclear matrix and are implicated in a number of degenerative diseases are called ________.
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A novel protist was discovered on a rock sample in a hot spring.Your task is to determine the lengths of DNA associated with its nucleosomes so that a colleague can then determine the nature of the proteins that comprise the nucleosome.How would you go about determining the lengths of these DNA fragments?
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The name given to double-stranded DNA that is twisted upon itself is ________.
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Which of the following model organisms were used in experiments demonstrating that DNA was the genetic material?
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Numerous Xenopus cells were exposed to varying amounts of ultraviolet light.Some of the resulting cells were observed to lack nucleoli.As a result,one would expect that the cell could not
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________ demonstrated that there were equivalent amounts of adenine and thymine and equivalent amounts of guanine and cytosine.
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