Exam 10: Conics and Calculus

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Find the arc length of the curve x=2t2,y=3t3 on the interval 1t4. Round x = 2 t ^ { 2 } , y = 3 t ^ { 3 } \text { on the interval } 1 \leq t \leq 4 \text {. Round } your answer to three decimal places.

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Find the arc length of the curve x=2t2,y=3t3 on the interval 1t4. Round x = 2 t ^ { 2 } , y = 3 t ^ { 3 } \text { on the interval } 1 \leq t \leq 4 \text {. Round } your answer to three decimal places.

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The path of a projectile is modeled by the parametric equations x=(85cos60)t and x = \left( 85 \cos 60 ^ { \circ } \right) t \text { and } y=(85sin60)t16t2y = \left( 85 \sin 60 ^ { \circ } \right) t - 16 t ^ { 2 } where xx and yy are measured in feet. Use a graphing utility to approximate the range of the projectile. Round your answer to two decimal places.

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Find the area of the surface generated by revolving the curve about the given axis. x=3cos3θ,y=3sin3θ,0θπ/2x = 3 \cos ^ { 3 } \theta , y = 3 \sin ^ { 3 } \theta , 0 \leq \theta \leq \pi / 2 (i) xx -axis;(ii) yy -axis

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 Find an equation of the tangent line at a point (0,0) on the curve \text { Find an equation of the tangent line at a point } ( 0,0 ) \text { on the curve } x=t24,y=t22tx = t ^ { 2 } - 4 , y = t ^ { 2 } - 2 t

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Find the arc length of the curve on the given interval. x=t2+3,y=8t3+9,1t0x = t ^ { 2 } + 3 , y = 8 t ^ { 3 } + 9 , - 1 \leq t \leq 0

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 Find dydx and d2ydt2 if possible, and find the slope and concavity (if possible) at the \text { Find } \frac { d y } { d x } \text { and } \frac { d ^ { 2 } y } { d t ^ { 2 } } \text { if possible, and find the slope and concavity (if possible) at the } point corresponding to t = 5. x=t+10 y=+4t

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Suppose a cable of a suspension bridge is suspended (in the shape of a parabola) between two towers that are 240 meters apart and 40 meters above the roadway as shown in the figure Given below. The cable touches the roadway midway between the towers. Find the length of the Parabolic supporting cable. Round your answer to two decimal places. Suppose a cable of a suspension bridge is suspended (in the shape of a parabola) between two towers that are 240 meters apart and 40 meters above the roadway as shown in the figure Given below. The cable touches the roadway midway between the towers. Find the length of the Parabolic supporting cable. Round your answer to two decimal places.

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Find the eccentricity of the ellipse given by (x+3)2+(y+1)21/16=1( x + 3 ) ^ { 2 } + \frac { ( y + 1 ) ^ { 2 } } { 1 / 16 } = 1

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Determine the t intervals on which the curve x=6t2,y=t33t is concave x = 6 t ^ { 2 } , y = t ^ { 3 } - 3 t \text { is concave } downward or concave upward.

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Earth moves in an elliptical orbit with the sun at one of the foci. The length of the half of the major axis is 149,598,000 kilometers, and the eccentricity is 0.0167. Find the maximum Distance (aphelion) of Earth from the sun. Round your answer to nearest kilometer.

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Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. y2+9y+2x4=0y ^ { 2 } + 9 y + 2 x - 4 = 0

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Determine the t intervals on which the curve x=6t2,y=t33t is concave x = 6 t ^ { 2 } , y = t ^ { 3 } - 3 t \text { is concave } downward or concave upward.

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Use the result, "the set of parametric equations for the ellipse is x=h+acosθ,y=k+bsinθx = h + a \cos \theta , y = k + b \sin \theta " to find a set of parametric equations for the ellipse with vertices (3,11)( 3,11 ) and (3,1)( 3,1 ) and with foci at (3,9)( 3,9 ) and (3,3)( 3,3 ) .

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 Find an equation of the hyperbola with vertices (0,5),(0,5) and asymptotes \text { Find an equation of the hyperbola with vertices } ( 0 , - 5 ) , ( 0,5 ) \text { and asymptotes } y=±16xy = \pm \frac { 1 } { 6 } x

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Find an equation of the hyperbola with vertices (7,0),(7,0) and asymptotes ( - 7,0 ) , ( 7,0 ) \text { and asymptotes } y=±2xy = \pm 2 x

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Find the focus of the parabola given by (x+4)+(y2)2=0( x + 4 ) + ( y - 2 ) ^ { 2 } = 0

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Find a polar equation for the hyperbola with its focus at the pole and vertices (20,0),(100,0)( 20,0 ) , ( 100,0 )

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Find the arc length of the curve on the given interval. x=t,y=3t2,0t3x = \sqrt { t } , y = 3 t - 2,0 \leq t \leq 3

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Find the foci of the ellipse given by (x4)2144+(y8)2400=1\frac { ( x - 4 ) ^ { 2 } } { 144 } + \frac { ( y - 8 ) ^ { 2 } } { 400 } = 1

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