Exam 7: Integration

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If we approximate 11x2+1dx\int_{1}^{\infty} \frac{1}{x^{2}+1} d x with 1b1x2+1dx\int_{1}^{b} \frac{1}{x^{2}+1} d x what value of b could we use to estimate the value of 11x2+1dx\int_{1}^{\infty} \frac{1}{x^{2}+1} d x with an error of less than 0.01? Of the following, select the smallest value of b that will work.

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B

Suppose that a computer takes 10710^{-7} seconds to add two numbers together, and it takes 10510^{-5} seconds to multiply two numbers together.The computer is asked to integrate the function f(x)=3x2f(x)=3 \cdot x^{2} from 0 to 1 using left hand sums with n divisions.As a function of n, let T(n)denote the time used by the computer to do the calculation.Compute T(n).(The computer figures x2 as x · x.)

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A

Find the area between f(x)=4xex2f(x)=4 x e^{-x^{2}} and g(x)= x for x \ge 0.Round to 3 decimal places.

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0.807

Use the table of antiderivatives to determine if the following statement is true. dxx22x+2=lnx+x22x+2+C\int \frac{d x}{\sqrt{x^{2}-2 x+2}}=\ln \left|x+\sqrt{x^{2}-2 x+2}\right|+C

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Suppose that as a storm dies down, its rainfall rate (in inches/hour)is given by y=10.09+t2y=\frac{1}{0.09+t^{2}} for 0 \le t \le 2, where t is the number of hours since the point of heaviest rainfall.What is the average rainfall rate over these two hours? Round your answer to 3 decimal places.

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Find the value of A if 03x2dx1+x2=3πA\int_{0}^{\sqrt{3}} \frac{x^{2} d x}{1+x^{2}}=\sqrt{3}-\frac{\pi}{A} .

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Derive the formula for the area of a circle of radius R using trigonometric substitution.

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Calculate sec2θdθ\int \sec ^{2} \theta d \theta

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Find (lnx)2dx\int(\ln x)^{2} d x .Hint: Integrate by parts.

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sin4xcos3xdx=15sin5x17sin7x+C\int \sin ^{4} x \cos ^{3} x d x=\frac{1}{5} \sin ^{5} x-\frac{1}{7} \sin ^{7} x+C .

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x2(2x2)dx=x422x33+C\int x^{2}(2 x-2) d x=\frac{x^{4}}{2}-\frac{2 x^{3}}{3}+C .

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7xlnxdx=72x2lnx+C\int 7 x \ln x d x=\frac{7}{2} x^{2} \ln x+C .

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Use the Fundamental Theorem to evaluate the definite integral 0πcos2xsinxdx\int_{0}^{\pi} \cos ^{2} x \sin x d x .Reduce fractions and leave them in the form "A/B".

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ex1+e2xdx=12arctan(ex)+C\int \frac{e^{x}}{1+e^{2 x}} d x=\frac{1}{2} \arctan \left(e^{x}\right)+C .

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Evaluate exactly: x/2x(sint)ecostdt\int_{x / 2}^{x}(\sin t) e^{\cos t} d t .

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Evaluate 01/711x2dx\int_{0}^{1 / 7} \frac{1}{1-x^{2}} d x to 3 decimal places.

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Consider the integral 0sin2x(1+x)2dx\int_{0}^{\infty} \frac{\sin ^{2} x}{(1+x)^{2}} d x .Which if the following is true?

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Find (1x+11(x+1)2)dx\int\left(\frac{1}{x+1}-\frac{1}{(x+1)^{2}}\right) d x .

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Consider the ellipse pictured below:  Consider the ellipse pictured below:   The perimeter of the ellipse is given by the integral  \int_{0}^{\pi / 2} 8 \sqrt{1-\frac{3}{4} \sin ^{2} \theta} d \theta  .It turns out that there is no elementary antiderivative for the function  f(\theta)=8 \sqrt{1-\frac{3}{4} \sin ^{2} \theta}  , and so the integral must be evaluated numerically.A graph of the integrand f( \theta )is shown below.   Calculate the right sum that approximates the definite integral with N = 4 equal divisions of the interval.Round to 4 decimal places. The perimeter of the ellipse is given by the integral 0π/28134sin2θdθ\int_{0}^{\pi / 2} 8 \sqrt{1-\frac{3}{4} \sin ^{2} \theta} d \theta .It turns out that there is no elementary antiderivative for the function f(θ)=8134sin2θf(\theta)=8 \sqrt{1-\frac{3}{4} \sin ^{2} \theta} , and so the integral must be evaluated numerically.A graph of the integrand f( θ\theta )is shown below.  Consider the ellipse pictured below:   The perimeter of the ellipse is given by the integral  \int_{0}^{\pi / 2} 8 \sqrt{1-\frac{3}{4} \sin ^{2} \theta} d \theta  .It turns out that there is no elementary antiderivative for the function  f(\theta)=8 \sqrt{1-\frac{3}{4} \sin ^{2} \theta}  , and so the integral must be evaluated numerically.A graph of the integrand f( \theta )is shown below.   Calculate the right sum that approximates the definite integral with N = 4 equal divisions of the interval.Round to 4 decimal places. Calculate the right sum that approximates the definite integral with N = 4 equal divisions of the interval.Round to 4 decimal places.

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(1+x)sin(4x)dx=cos4x4+xcos4x4sin4x16+C\int(1+x) \sin (4 x) d x=-\frac{\cos 4 x}{4}+\frac{x \cos 4 x}{4}-\frac{\sin 4 x}{16}+C .

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