Exam 12: Parametric Equations and Polar Coordinates

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Find a Cartesian equation for the line whose polar equation is given. - rcos(θ+4π3)=23r \cos \left( \theta + \frac { 4 \pi } { 3 } \right) = 2 \sqrt { 3 }

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Graph. - x2+25y2=25x^{2}+25 y^{2}=25  Graph. - x^{2}+25 y^{2}=25

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Find the directrices of the ellipse. - 16x2+81y2=129616 x ^ { 2 } + 81 y ^ { 2 } = 1296

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The eccentricity is given of a conic section with one focus at the origin, along with the directrix corresponding to that focus. Find a polar equation for the conic section. -e = 2, y = -7

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Find the foci of the ellipse. - 81x2+36y2=291681 x ^ { 2 } + 36 y ^ { 2 } = 2916

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Find the area of the specified region. -Inside the circle r=3sinθr = \sqrt { 3 } \sin \theta and outside the cardioid r=1+cosθr = 1 + \cos \theta

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Find the length of the curve. -The parabolic segment r=31+cosθ,0θπ2r = \frac { 3 } { 1 + \cos \theta } , 0 \leq \theta \leq \frac { \pi } { 2 }

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Graph. - 36x2+12y2=19236 x^{2}+12 y^{2}=192  Graph. - 36 x^{2}+12 y^{2}=192

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Find an equation for the line tangent to the curve at the point defined by the given value of t. - x=t,y=2t,t=18\mathrm { x } = \mathrm { t } , \mathrm { y } = \sqrt { 2 \mathrm { t } } , \mathrm { t } = 18

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Find the directrices of the hyperbola. - y236x2=36y ^ { 2 } - 36 x ^ { 2 } = 36

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Graph. - 16x29y2=14416 x^{2}-9 y^{2}=144  Graph. - 16 x^{2}-9 y^{2}=144

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Determine the symmetries of the curve. - r=5θr = 5 \theta

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Find the standard-form equation for a hyperbola which satisfies the given conditions. -A hyperbola centered at the origin having focus at (9,0)( 9,0 ) and eccentricity equal to 32\frac { 3 } { 2 }

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Find the foci of the hyperbola. - 4y225x2=1004 y ^ { 2 } - 25 x ^ { 2 } = 100

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Graph the pair of parametric equations with the aid of a graphing calculator. - x=7t7sint,y=77cost,2πt2πx=7 t-7 \sin t, y=7-7 \cos t,-2 \pi \leq t \leq 2 \pi  Graph the pair of parametric equations with the aid of a graphing calculator. - x=7 t-7 \sin t, y=7-7 \cos t,-2 \pi \leq t \leq 2 \pi

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Find the directrices of the hyperbola. - x2y2=25x ^ { 2 } - y ^ { 2 } = 25

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Find the vertices and foci of the ellipse. - x2400+y2144=1\frac { x ^ { 2 } } { 400 } + \frac { y ^ { 2 } } { 144 } = 1

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Graph. - 9x24y2=369 x^{2}-4 y^{2}=36  Graph. - 9 x^{2}-4 y^{2}=36

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Replace the Cartesian equation with an equivalent polar equation. - x2+(y25)2=625x ^ { 2 } + ( y - 25 ) ^ { 2 } = 625

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Solve the problem. -Find the foci and asymptotes of the following hyperbola: x2y2=32x ^ { 2 } - y ^ { 2 } = 32

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