Exam 13: Genes, Chromosomes, and Human Genetics
Chemical compounds released during tobacco use can cause ____.
C
Turner Syndrome (XO) is the only viable monosomy found in humans. Some sex chromosome trisomies are also viable, including XXX, XXY, and XYY. There are no viable autosomal monosomies, and a small handful of viable autosomal trisomies exist, such as trisomy 21 (Down syndrome), and trisomy 13 and 18, both of which are lethal within the first year of life. Clearly, aneuploidy is not tolerated well in humans. Speculate as to why there are so few viable monosomies (only one) in humans, and why there are so few viable trisomies. Also, speculate as to why aneuploidy involving the sex chromosomes is better tolerated than those involving autosomes.
Monosomic cells are missing an entire chromosome. Because only one monosomy is viable, this suggests human cells must require two of each chromosome to function normally. Possibly, some autosomal genes must be present in two copies to achieve adequate expression levels in order to be functional for the cell. Trisomic cells have an extra copy of a chromosome. Due to the low tolerance for human trisomies, human cells seem to require only two copies of each gene, and having three copies of some genes is lethal as there may be too much gene function. The few viable autosomal trisomies are either lethal shortly after birth (trisomy 13 and 18) or have a variety of associated symptoms, including a slightly shortened lifespan (trisomy 21). During human development, all X chromosomes beyond one per cell are inactivated. Therefore, aneuploidy is better tolerated when involving sex chromosomes because there is already a natural process in place for partially "haploidizing" those chromosomes. Despite this, there are symptoms associated with XO, XXY, XYY, and XXX individuals.
In Drosophila melanogaster, the gene for eye color is located on the X chromosome. The allele for red eye color (Xw+) is dominant over the allele for white eye color (Xw). You examine a vial of 100 flies that are all offspring from a single genetic cross. You see only red-eyed females present, but you see both red-eyed and white-eyed males present. The genotypes of the parents were ____.
Which statement correctly describes autosomal recessive inheritance?
You are genetic counselor, and a couple comes to you with concerns that if they have a child together, he or she could have sickle-cell anemia. Genetic tests reveal that both the man and woman are carriers for sickle-cell anemia. How should you advise them?
During normal human embryonic development, if ____, then the SRY gene switches development toward ____.
For most multicellular eukaryotes, including humans, mitochondria are inherited ____.
Explain the difference in meiotic products that arise when nondisjunction occurs during the first meiotic division versus those that arise when nondisjunction occurs during the second meiotic division.
When two genes are located on different chromosomes, ____ of the offspring from a testcross for genetic linkage should have a recombinant phenotype.
Which process results in the production of offspring who are recombinant for two genes on the same chromosome?
In humans, a deletion from chromosome 5 typically leads to severe mental retardation and a malformed larynx; this disorder is known as ____.
An individual who is a carrier of a genetically inherited disease ____.
If you see a male calico cat, you can be fairly certain that his diploid cells have a sex chromosome combination of ____.
You are a genetic counselor, and a couple comes to you with concerns that if they have a child together, he or she could have cystic fibrosis. Genetic tests reveal that the woman is a carrier for cystic fibrosis, but the man is not. How should you advise them?
A mutation in the human gene for a fibroblast growth factor receptor (FGFR) appears to be responsible for ____.
Figure 13.5a
Which genetic condition is revealed in the karyotype display shown in the accompanying figure?

Filters
- Essay(0)
- Multiple Choice(0)
- Short Answer(0)
- True False(0)
- Matching(0)