Exam 13: Spontaneous Change: Entropy and Gibbs Energy

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For the reaction PCl5(g)→ PCl3(g)+ Cl2(g)at 298 K,Keq = 1.87 × 10-7,what is ΔrG ° and is the reaction spontaneous?

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The maximum quantity of energy available for useful work is:

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Find correct statements. I.A spontaneous process is a process that occurs in a system left to itself. II.A non spontaneous process will not occur unless some external force is applied. III.If a reaction is spontaneous,the reverse is also spontaneous. IV.Only spontaneous processes occur naturally. V.Entropy is inversely proportional to the degree of randomness.

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The following reaction is exothermic. 2 N2O(g)→ 2 N2(g)+ O2(g) This means the reaction:

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A reaction is spontaneous if: I.ΔG is a negative value II.both enthalpy and entropy increase III.ΔH is negative and ΔS is positive IV.both enthalpy and entropy decrease V.ΔH is positive and ΔS is negative

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What is ΔrG°? What is Δ<sub>r</sub>G°?

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Which of the following has the highest entropy?

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For the reaction For the reaction   What is D<sub>r</sub>S<sup>o</sup>? <sup> </sup> What is DrSo?

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What is ΔrG° at 25 °C? CO(g)+ 2 H2(g)→ CH3OH(g)ΔrH° = -90.7 kJ ΔrS° = -221 J/K

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What is ΔrG°? What is Δ<sub>r</sub>G°?

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?rG ? is independent of temperature.

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Calculate ΔrG° for the reaction Cu(s)+ H2O(g)→ CuO(s)+ H2(g)at 500 K. Calculate Δ<sub>r</sub>G° for the reaction Cu(s)+ H<sub>2</sub>O(g)→ CuO(s)+ H<sub>2</sub>(g)at 500 K.

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What is ΔrG° at 25 °C? 2O3(g)→ 3 O2(g)ΔrH° = -284 kJ ΔrS° = 139 J/K

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The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  . The specific heats of ice,water,and steam are The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  . The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  . And The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  . Respectively.For The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  . O, The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  . = 6.01 kJ mol-1,and The enthalpy change for converting 1.00 mol of ice at -50.0 °C to water at 70.0 °C is   The specific heats of ice,water,and steam are     And   Respectively.For   O,   = 6.01 kJ mol<sup>-1</sup>,and  ..

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For the reaction I2(s)+ Cl2(g)→ 2 ICl(g),ΔrH = 36 kJ/mol,and ΔrS = 158.8 J/mol K at 25 °C.Calculate the temperature at which Keq is 4.0 × 103.

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Predict whether ΔS is positive or negative for the following process: H2(g)+ 1/2 O2(g)→ H2O(g)

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Which of the following best expresses the increase in entropy associated with melting and sublimation,respectively?

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The entropy of a system always increases for a spontaneous process.

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A spontaneous process will occur only if an external action is continually applied.

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The entropy of a pure perfect crystal at 25 K is zero.

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