Exam 8: Nomenclature and Noncovalent Intermolecular Interactions

arrow
  • Select Tags
search iconSearch Question
  • Select Tags

When two hydrocarbon molecules (such as hexane), initially dissolved in water, come together to form an aggregate in water, two of the following are true.

Free
(Multiple Choice)
4.9/5
(42)
Correct Answer:
Verified

D, E

This is the predominant form of the sugar D-glucose. This is the predominant form of the sugar D-glucose.    Glucose does not passively cross cell membranes, even though it is a neutral molecule. Explain why. Glucose does not passively cross cell membranes, even though it is a neutral molecule. Explain why.

Free
(Essay)
4.9/5
(39)
Correct Answer:
Verified

The cell membrane consists of a lipid bilayer, where the outside of the layer contains the hydrophilic head groups and the inner portion contains the hydrophobic tails. In order to pass through the cell membrane through passive diffusion, the molecule must not be insoluble in hydrocarbons, nor highly soluble in hydrocarbons. Small neutral molecules like molecular oxygen can pass through, but glucose is a much larger molecule. While it contains six carbon atoms, it also contains five hydrophilic hydroxy groups that will not be able to pass through the hydrocarbon tails. In the body, glucose requires carrier proteins that help it to cross cell membranes.

The boiling point of pentane is 36 °C. The compound with the highest boiling point is

Free
(Multiple Choice)
4.7/5
(42)
Correct Answer:
Verified

C

In each case, identify the better solvent for dissolving the compounds. Choose between H2O (ε = 78) or benzene (ε = 2.3). (Benzene is a six-carbon cyclic hydrocarbon.) In each case, identify the better solvent for dissolving the compounds. Choose between H<sub>2</sub>O (ε = 78) or benzene (ε = 2.3). (Benzene is a six-carbon cyclic hydrocarbon.)

(Short Answer)
4.9/5
(39)

In which solvent should NaCl (an ionic compound) have the greatest solubility? (ε = dielectric constant.) Explain your choice briefly. In which solvent should NaCl (an ionic compound) have the greatest solubility? (ε = dielectric constant.) Explain your choice briefly.

(Essay)
4.8/5
(42)

Sodium chloride, an ionic compound, should be most soluble in which solvent? ( = dielectric constant) (a) hexane (ϵ=2)( \epsilon = 2 ) (b)  Sodium chloride, an ionic compound, should be most soluble in which solvent? (<font face=symbol></font> = dielectric constant) (a) hexane  ( \epsilon = 2 )   (b)   acetone  ( \epsilon = 19 )   (c)    N -methylpyrrolidone  ( \epsilon = 32 )   (d)    \text { N., } \text {-dimethylformamide }(\epsilon=37)    (e)   dimethylsulfoxide  ( \epsilon = 47 ) acetone (ϵ=19)( \epsilon = 19 ) (c)  Sodium chloride, an ionic compound, should be most soluble in which solvent? (<font face=symbol></font> = dielectric constant) (a) hexane  ( \epsilon = 2 )   (b)   acetone  ( \epsilon = 19 )   (c)    N -methylpyrrolidone  ( \epsilon = 32 )   (d)    \text { N., } \text {-dimethylformamide }(\epsilon=37)    (e)   dimethylsulfoxide  ( \epsilon = 47 ) NN -methylpyrrolidone (ϵ=32)( \epsilon = 32 ) (d)  Sodium chloride, an ionic compound, should be most soluble in which solvent? (<font face=symbol></font> = dielectric constant) (a) hexane  ( \epsilon = 2 )   (b)   acetone  ( \epsilon = 19 )   (c)    N -methylpyrrolidone  ( \epsilon = 32 )   (d)    \text { N., } \text {-dimethylformamide }(\epsilon=37)    (e)   dimethylsulfoxide  ( \epsilon = 47 )  N., -dimethylformamide (ϵ=37)\text { N., } \text {-dimethylformamide }(\epsilon=37) (e)  Sodium chloride, an ionic compound, should be most soluble in which solvent? (<font face=symbol></font> = dielectric constant) (a) hexane  ( \epsilon = 2 )   (b)   acetone  ( \epsilon = 19 )   (c)    N -methylpyrrolidone  ( \epsilon = 32 )   (d)    \text { N., } \text {-dimethylformamide }(\epsilon=37)    (e)   dimethylsulfoxide  ( \epsilon = 47 ) dimethylsulfoxide (ϵ=47)( \epsilon = 47 )

(Multiple Choice)
4.8/5
(26)

Dissolving hexane in water has

(Multiple Choice)
4.9/5
(28)

Draw the structure of 3-hexyn-2-ol.

(Essay)
4.8/5
(33)

Name the compound. Include the appropriate stereochemical designation in the name. Name the compound. Include the appropriate stereochemical designation in the name.

(Short Answer)
4.8/5
(36)

Consider the equilibria in CCl4, an apolar, aprotic, nondonor solvent. Consider the equilibria in CCl<sub>4</sub>, an apolar, aprotic, nondonor solvent.    Explain why replacing the two carbons of the ring shown above with oxygens makes the axial conformation more stable. Explain why replacing the two carbons of the ring shown above with oxygens makes the axial conformation more stable.

(Essay)
4.7/5
(34)

Draw all the alcohols having a molecular formula of C4H10O. a. Indicate if the alcohol is chiral. b. Name each alcohol using IUPAC nomenclature. c. Classify each alcohol as primary, secondary or tertiary.

(Essay)
4.8/5
(31)

When DMSO dissolves potassium chloride (K+ Cl), what is the solvation of the salt due to? When DMSO dissolves potassium chloride (K<sup>+</sup> Cl<sup>−</sup>), what is the solvation of the salt due to?

(Multiple Choice)
4.8/5
(28)

Drugs are often conjugated to glucuronic acid groups in biological systems. Explain why you would need to conjugate a drug to glucuronic acid and how glucuronides solve this problem. Drugs are often conjugated to glucuronic acid groups in biological systems. Explain why you would need to conjugate a drug to glucuronic acid and how glucuronides solve this problem.

(Essay)
5.0/5
(35)

Name the compound with an IUPAC systematic name. Name the compound with an IUPAC systematic name.

(Essay)
4.8/5
(34)

Arrange these compounds in order of increasing boiling point (lowest boiling point first). Arrange these compounds in order of increasing boiling point (lowest boiling point first).

(Multiple Choice)
4.9/5
(38)

Draw the structure of 3-ethoxy-2-butanethiol (alternate name 3-ethoxybutane-2-thiol).

(Essay)
4.8/5
(30)

Which compound would form the strongest complex with potassium ion? Which compound would form the strongest complex with potassium ion?

(Multiple Choice)
4.8/5
(38)

Select the structure of the compound with the highest boiling point. (a) ClCH2CH2CH2Cl\mathrm{Cl}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{Cl} (b) ClCH2CH2CH2Cl\mathrm { Cl } - \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } - \mathrm { Cl } (c) CH3CH2CH2CH2OH\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } - \mathrm { OH } (d)  Select the structure of the compound with the highest boiling point. (a)  \mathrm{Cl}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{Cl}    (b)   \mathrm { Cl } - \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } - \mathrm { Cl }   (c)   \mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } - \mathrm { OH }   (d)

(Multiple Choice)
4.7/5
(37)

Provide a systematic name for the compound, including any stereochemical designations. Provide a systematic name for the compound, including any stereochemical designations.

(Short Answer)
4.8/5
(32)

By circling three items below each structure, classify each of the following solvents as polar or apolar, donor or nondonor, protic or aprotic.  By circling three items below each structure, classify each of the following solvents as polar or apolar, donor or nondonor, protic or aprotic.        \begin{array}{c} \begin{array}{lc} \text { polar } & \text { apolar } \\ \text { donor } & \text { nondonor } \\ \text { protic } & \text { aprotic } \end{array}  \begin{array}{ll} \text { polar } & \text { apolar } \\ \text { donor } & \text { nondonor } \\ \text { protic } & \text { aprotic } \end{array} \end{array}    By circling three items below each structure, classify each of the following solvents as polar or apolar, donor or nondonor, protic or aprotic.        \begin{array}{c} \begin{array}{lc} \text { polar } & \text { apolar } \\ \text { donor } & \text { nondonor } \\ \text { protic } & \text { aprotic } \end{array}  \begin{array}{ll} \text { polar } & \text { apolar } \\ \text { donor } & \text { nondonor } \\ \text { protic } & \text { aprotic } \end{array} \end{array}   polar apolar donor nondonor protic aprotic polar apolar donor nondonor protic aprotic

(Essay)
4.9/5
(36)
Showing 1 - 20 of 25
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)